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How do you find the the center of a circle and its radius when its equation is x squared plus y squared equals 12x -10y -12?
Wiki User
∙ 11y ago
Remember that: (x-a)2+(y-b)2 = radius2 whereas a and b are the coordinates of the circles centre
Rearrange the equation: x2-12x+y2+10y = -12
Complete the squares: (x-6)2+(y+5)2 = 36+25-12 => 49
Therefore: centre = (6, -5) and radius = 7
Wiki User
∙ 11y ago
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What is the center of a circle for the equation 3x2 plus 3y2 - 30x plus 27 equals 0?
56
Is four y squared plus nine equals 4 a linear equation?
No, it is not.No, it is not.
What is the center and radius of a circle with an equation of x squared plus y squared - 10x plus 6y equals 47?
The equation of the circle with center (h, k) and radius r is of the form(x - h)2 + (y - k)2 = r2x2 + y2 - 10x + 6y = 47 (complete the square)[x2 - 10x + (10/2)2] + [y2 + 6y +(6/2)2] = 47 + (10/2)2 +(6/2)2(x2 - 10x + 52) + (y2 + 6y + 32) = 47 + 52 + 32(x - 5)2 + (y + 3)2 = 81(x - 5)2 + (y + 3)2 = 92So that the center of the circle is (5, -3) and the radius is 9.
What is the area of a circle whose equation is x squared plus y squared -10x plus 6y -15 equals 0?
Equation: x^2 +y^2 -10x +6y -15 = 0 Completing the squares: (x-5)^2 +(y+3)^2 -25 -9 -15 = 0 So: (x-5)^2 +(y+3)^2 = 49 which is the radius of the circle squared Area of the circle: 49*pi = 154 square units rounded to the nearest integer
Find the equations of the lines that are tangent to the ellipse x squared plus y squared equals sixteen and that also pass through the point x equals 4 and y equals 6?
This is not possible, since the point (4,6) lies inside the circle : X2 + Y2 = 16 Tangents to a circle or ellipse never pass through the circle
Where is the center of the circle given by the equation x - 3 squared plus y plus 2 squared equals 9?
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
Where is the center of the circle given by the equation x plus 4 squared plus y plus 6 squared equals 49?
(-4,-6)
How do you graph the equation x squared plus y squared equals 16?
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 squared equals 25?
The centre is (-5, 3)
How do you solve x squared plus y squared equals 13?
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Where is the center of the circle given by the equation x plus 7 2 plus y - 5 2 equals 16 Enter your answer as an ordered pair?
I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5
Does the equation a squared plus b squared equals c squared classify as a quadratic equation?
no
What is the equation for a circle with its center at the origin and a tangent whose equation is y equals 7?
x2 + y2 = 49
Is c equals 2πr the same as c equals πr squared?
No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).
What is the approximate area of a circle with a radius of 3 feet?
Area of a circle equals pi (~3.14) multiplied by the radius squared. So to find the area of that circle your equation is (3.14)(3)^2 which equals approximately 27.
What is the center of a circle for the equation 3x2 plus 3y2 - 30x plus 27 equals 0?
56
Where is the center of the circle given by the equation x plus 5 times 2 plus y - 3 times 2 equals 25 in an ordered pair?
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.
