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How do you solve x minus 4 equals negative y?
given: x - 4 = -y or, -y = x - 4 or, y = -(x - 4) or y = -x + 4 or y = 4 - x i.e. for x > 4, the equation x - 4 = -y is true.
How do you evaluate and write this question in simplest form x over y for x equals 4 and y equals 4 what is the answer?
Evaluate x/y when x = 4 and y = 4. x/y = 4/4 = 1/1 = 1
What are y equals x plus 2 y equals -x plus 4?
y = x + 2 y = -x + 4 x + 2 = -x + 4 2x + 2 = 4 2x = 2 x = 1 y = x + 2 y = 1 + 2 y = 3 (1, 3)
What is the answer to x equals x-4 divided by y?
x=x-4/y 0=-4/y 0=-4 This equation is not well put together. I may have interpreted it wrong. This may be your equation and you didn't state that x-4 is a quantity x=(x-4)/y x-4=xy y=1-4/x y=-4x-1 + 1 This is slope intercept form. Your slope is -4/1 and your y-intercept is +1
Use the graph to solve the system of linear equations x - y=4 4x + y=1?
x=4+y 4x+y=1 = 4(4+y)+y=1 16+4y+y=1 16+5y=1 5y=-15 y=-3 x=4+y = x=4+(-3) x=1
How do you solve x minus 4 equals negative y?
given: x - 4 = -y or, -y = x - 4 or, y = -(x - 4) or y = -x + 4 or y = 4 - x i.e. for x > 4, the equation x - 4 = -y is true.
If y ( x ) 4 x what is x when y ( x ) 4?
y=-x+4
How do you find the x and y intercept in the equation x plus y equals 4?
x + y = 4 or y = -x + 4 To get X-intercept, make y = 0, then 0 = -x + 4, or x = 4To get Y-intercept, make x = 0, then y = -0 + 4, or y = 4
X the power of 4 times y times x to the power of 5 times y?
x^(4)*y*x^(5)*yMultiply x^(4) by y to get x^(4)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(4)y*x^(5)*yMultiply x^(4)y by x^(5) to get x^(9)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y*yMultiply x^(9)y by y to get x^(9)y^(2).(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y^(2)To find the derivative of x^(9)y^(2), multiply the base (x) by the exponent (9), then subtract 1 from the exponent.(d)/(dx) x^(4)*y*x^(5)*y=9x^(8)y^(2)The derivative of x^(4)*y*x^(5)*y is 9x^(8)y^(2).9x^(8)y^(2)
What is the solution of X-Y-4 by graphing?
x-y=4 x=y+4
Write an algorithm to swap the values of two variables?
x=9; y=4; x=x+y; #x=13;y=4; y=x-y; #y=13-4=9; x=x-y; #x=13-9=4;
How do you evaluate and write this question in simplest form x over y for x equals 4 and y equals 4 what is the answer?
Evaluate x/y when x = 4 and y = 4. x/y = 4/4 = 1/1 = 1
What is x y 12 and x - y 4 using the addition method?
16
X plus y equals 4 x-y equals 4?
8
What is the intersection of these two lines 2x plus 4 equals y and x - y equals 2?
2x + 4 = y ...............2x + 4 = y ....................2x + 4 = y .............2*(-6)+ 4 = y x - y = 2 .......<=> ...x - 2x - 4 = 2 .....<=> ...x = -6......... <=>.... x = -6 ..............<=> y = - 8 x = - 6
How do you solve x equals 4 y equals x plus 3?
x=4 y=x+3 y=4+3 y=7
What are y equals x plus 2 y equals -x plus 4?
y = x + 2 y = -x + 4 x + 2 = -x + 4 2x + 2 = 4 2x = 2 x = 1 y = x + 2 y = 1 + 2 y = 3 (1, 3)
