Y = 4/x^2
To solve for x when z equals y divided by x, you can rearrange the equation to isolate x. Start by multiplying both sides by x to get xz = y. Then, divide both sides by z to solve for x, giving you x = y/z. This is the solution for x when z equals y divided by x.
Oh, dude, let's break it down! If X divided by Y equals 420, that means X is 420 times Y. So, technically, X could be any multiple of 420, and Y could be any number that isn't zero. It's like a math riddle, but not really a riddle because the answer is pretty straightforward.
It depends on how y depends on x.
xy = x ÷x y = 1
y=x+2if y=66=x+26-2=x4=xso x=4
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
(x2 + y2)(x + y)(x - y) = x4 - y4.
x2 / y = (6)2 /2 = 36/2 = 18
Y = 4/x^2
0.6667
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
200
y = mx + b
Sorry but i dont know te answer to this :( x/a= y/b therefore x = ay/b
A lot of answers... for example, 49 divided 7 equals 7.
Y / (2+x)If x = -1 and y=2, thenY / (2+x) = 2/(2-1) = 2/1 = 2