If we were to graph the number it would be:
y = x
If we were to graph the square it would be:
y = x²
The difference would be:
f(x) = x - x²
You want to maximize this difference, so take the derivative:
f'(x) = 1 - 2x
Then set it to zero:
0 = 1 - 2x
Add 2x to both sides:
2x = 1
Divide both sides by 2:
x = ½
Answer: ½ is the number that most exceeds its square.
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
The problem can be written as3x2 = 6x + 9x is the number we want to findSolution:x2 = 2x + 3x2 - 2x - 3 = 0(x-3)(x+1) = 0x = -1, 3
If the square root is an integer, it's a square number.
Sometimes the square root of a positive number can be irrational, as in the square root of 2 (which is a non-perfect square number), but sometimes it is a rational number, as in the square root of 25 (which is a perfect square number).
The square of 9 more than a number is equal to nine more than the square of a number. What is the number?
31 squared = 961. 32 squared = 1,024. The first prime number that is greater than 32 is 37. Therefore, 37 is the first prime number whose square exceeds 1,000.
A square number.
A square number
If the circle is inside the square, four.
Russia just barely exceeds that number, and it's the only one.
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
A perfect square
8
There's no set amount.
A perfect square
"7" is the number because its square root is "49" & 49+7=56
The maximum number of different phenotypes available in a dihybrid cross with 16 boxes in a Punnett square is 4. This is because there are four possible combinations of alleles for two traits that can segregate independently.