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If we were to graph the number it would be:

y = x

If we were to graph the square it would be:

y = x²

The difference would be:

f(x) = x - x²

You want to maximize this difference, so take the derivative:

f'(x) = 1 - 2x

Then set it to zero:

0 = 1 - 2x

Add 2x to both sides:

2x = 1

Divide both sides by 2:

x = ½

Answer: ½ is the number that most exceeds its square.

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Q: What number exceeds its square by the maximum amount?
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If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.


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