If we were to graph the number it would be:
y = x
If we were to graph the square it would be:
y = x²
The difference would be:
f(x) = x - x²
You want to maximize this difference, so take the derivative:
f'(x) = 1 - 2x
Then set it to zero:
0 = 1 - 2x
Add 2x to both sides:
2x = 1
Divide both sides by 2:
x = ½
Answer: ½ is the number that most exceeds its square.
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
The problem can be written as3x2 = 6x + 9x is the number we want to findSolution:x2 = 2x + 3x2 - 2x - 3 = 0(x-3)(x+1) = 0x = -1, 3
If the square root is an integer, it's a square number.
Sometimes the square root of a positive number can be irrational, as in the square root of 2 (which is a non-perfect square number), but sometimes it is a rational number, as in the square root of 25 (which is a perfect square number).
The square of 9 more than a number is equal to nine more than the square of a number. What is the number?
31 squared = 961. 32 squared = 1,024. The first prime number that is greater than 32 is 37. Therefore, 37 is the first prime number whose square exceeds 1,000.
A square number.
A square number
If the circle is inside the square, four.
Russia just barely exceeds that number, and it's the only one.
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
A perfect square
8
There's no set amount.
A perfect square
"7" is the number because its square root is "49" & 49+7=56
TANK 1 With 200 crickets occupying an area of 0.80 square meters, that gives a population density of . . 200 crickets -------------------------- = ? crickets / square meter 0.80 square meters Is that amount < or = or > the maximum of 210 crickets / square meter?. = = = = = = = = = = = = = = = = = = = = = = = = = TANK 2 With 150 crickets occupying an area of 0.80 square meters, that gives a population density of . . 150 crickets --------------------------- = ? crickets / square meter 0.80 square meters Is that amount < or = or > the maximum of 210 crickets / square meter?. = = = = = = = = = = = = = = = = = = = = = = = = = TANK 3 With 315 crickets occupying an area of 1.5 square meters, that gives a population density of . . 315 crickets ------------------------- = ? crickets / square meter 1.5 square meters Is that amount < or = or > the maximum of 210 crickets / square meter?. = = = = = = = = = = = = = = = = = = = = = = = For PROBLEM #1, when you move crickets from tank to tank, remember to change the value of the numerators in the fractions above. EXAMPLE If you remove 10 crickets from tank 2 and put them in tank 3, then decrease tank 2's numerator from 150 to 140 and increase tank 3's numerator from 315 to 325. For PROBLEM #2, we need to rearrange the formula from above (number of crickets) -------------------------- = population density . . . . (area) Multiply both sides of the equal sign by (area). (area)(number of crickets) ----------------------------------- = (area)(population density) . . . . . . . (area) Notice how the (area) on the left side cancels out? (number of crickets) = (area)(population density) (number of crickets) = (250 square meters)(2.4 crickets / square meter) (number of crickets) = ?