If we were to graph the number it would be:
y = x
If we were to graph the square it would be:
y = x²
The difference would be:
f(x) = x - x²
You want to maximize this difference, so take the derivative:
f'(x) = 1 - 2x
Then set it to zero:
0 = 1 - 2x
Add 2x to both sides:
2x = 1
Divide both sides by 2:
x = ½
Answer: ½ is the number that most exceeds its square.
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
The problem can be written as3x2 = 6x + 9x is the number we want to findSolution:x2 = 2x + 3x2 - 2x - 3 = 0(x-3)(x+1) = 0x = -1, 3
If the square root is an integer, it's a square number.
Sometimes the square root of a positive number can be irrational, as in the square root of 2 (which is a non-perfect square number), but sometimes it is a rational number, as in the square root of 25 (which is a perfect square number).
The square of 9 more than a number is equal to nine more than the square of a number. What is the number?
31 squared = 961. 32 squared = 1,024. The first prime number that is greater than 32 is 37. Therefore, 37 is the first prime number whose square exceeds 1,000.
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
Russia just barely exceeds that number, and it's the only one.
The symbol for exceeds is ">" which means "greater than".
"7" is the number because its square root is "49" & 49+7=56
46
105
69
There can be no such number. Since if x is such a number then 4x is a square number with more factors. and if 4x is the number then 16x has more, etc.
the base of the rectangle exceeds three times its altitudes by 4. if the length of the side of the square is 8centimeter find the dimension of the rectangle.
There is no generally agreed-upon concept or number that is considered to be "above" Graham's number. Graham's number is so large that it exceeds what can be effectively comprehended or meaningfully compared to other numbers in most contexts.
It is: 4125+598 = 4723