200
7 subtracted from the quotient of a number and 2 is a -6
If the number is x then: x+4-9 = -2 and so x = 3
to multiply fractions add them together and reduce the final fraction. to multiply mixed numbers, first make the mixed number an improper fraction, by mulitplying the whole number and the denominator and adding the answer to the numerator. Example: The improper fraction 8/5 can be changed to the mixed number 1 3/5 by dividing the numerator (8) by the denominator (5). This gives a quotient of 1 and a remainder of 3. The remainder is placed over the divisor (5).
To convert the improper fraction 6/21 into a mixed number, you divide the numerator (6) by the denominator (21). This division gives you a quotient of 0 with a remainder of 6. Therefore, the mixed number equivalent of 6/21 is 0 6/21 or simply 6/21.
what divided by 2= 162
99
The quotient is 47 with a remainder of 1
To find the number that gives a quotient of 5 and a remainder of 3 when divided by 7, we can use the formula: ( \text{number} = \text{divisor} \times \text{quotient} + \text{remainder} ). Here, the divisor is 7, the quotient is 5, and the remainder is 3. So, the calculation is ( 7 \times 5 + 3 = 35 + 3 = 38 ). Therefore, the number is 38.
3 divided by 2 gives 1r1
236 divided by 5 is 47 with remainder 1
2351
62 explanation is : 4X15+2=62
49, when divided by 7, gives a quotient of 7
10.102
I think you're wanting a number of two digits, one of which is 3, that when divided by 7 gives a quotient and a remainder of 1 and when that quotient is divided by 2 it gives a remainder of 1: Answer: 36 36 ÷ 7 = 5 r 1 5 ÷ 2 = 2 r 1 If you want the number to be such that if it is divided by 7 the remainder is 1 and if it is divided by 2 the remainder is 1, then: Answer: 43 43 ÷ 7 = 6 r 1 43 ÷ 2 = 21 r 1
According to division algorithm: Dividend = Divisor x Quotient + Remainder Dividend = 58 x 40 + 31 = 2341. So 2341 is the required number.
4.8333