2351
According to division algorithm: Dividend = Divisor x Quotient + Remainder Dividend = 58 x 40 + 31 = 2341. So 2341 is the required number.
237 is a COMPOSITE number. Since it is divided by 3 and gives a quotient of 79 (which is a prime factor of 237) and remainder as 0.
447
In the division problem 467 ÷ 34, the quotient is the result of dividing 467 by 34, which is 13.735294118. The remainder is the amount left over after dividing as much as possible, which in this case is 11. This means that 467 divided by 34 equals 13 with a remainder of 11.
200
99
The quotient is 47 with a remainder of 1
In the division problem 467 ÷ 34, the quotient is the result of dividing 467 by 34, which is 13.735294118. The remainder is the amount left over after dividing as much as possible, which in this case is 11. This means that 467 divided by 34 equals 13 with a remainder of 11.
3 divided by 2 gives 1r1
236 divided by 5 is 47 with remainder 1
2351
62 explanation is : 4X15+2=62
49, when divided by 7, gives a quotient of 7
10.102
I think you're wanting a number of two digits, one of which is 3, that when divided by 7 gives a quotient and a remainder of 1 and when that quotient is divided by 2 it gives a remainder of 1: Answer: 36 36 ÷ 7 = 5 r 1 5 ÷ 2 = 2 r 1 If you want the number to be such that if it is divided by 7 the remainder is 1 and if it is divided by 2 the remainder is 1, then: Answer: 43 43 ÷ 7 = 6 r 1 43 ÷ 2 = 21 r 1
According to division algorithm: Dividend = Divisor x Quotient + Remainder Dividend = 58 x 40 + 31 = 2341. So 2341 is the required number.