467 divided by 34 gives you a quotient of 13 and a remainder of 25.
2351
According to division algorithm: Dividend = Divisor x Quotient + Remainder Dividend = 58 x 40 + 31 = 2341. So 2341 is the required number.
237 is a COMPOSITE number. Since it is divided by 3 and gives a quotient of 79 (which is a prime factor of 237) and remainder as 0.
447
200
99
The quotient is 47 with a remainder of 1
467 divided by 34 gives you a quotient of 13 and a remainder of 25.
3 divided by 2 gives 1r1
236 divided by 5 is 47 with remainder 1
2351
62 explanation is : 4X15+2=62
49, when divided by 7, gives a quotient of 7
10.102
I think you're wanting a number of two digits, one of which is 3, that when divided by 7 gives a quotient and a remainder of 1 and when that quotient is divided by 2 it gives a remainder of 1: Answer: 36 36 ÷ 7 = 5 r 1 5 ÷ 2 = 2 r 1 If you want the number to be such that if it is divided by 7 the remainder is 1 and if it is divided by 2 the remainder is 1, then: Answer: 43 43 ÷ 7 = 6 r 1 43 ÷ 2 = 21 r 1
According to division algorithm: Dividend = Divisor x Quotient + Remainder Dividend = 58 x 40 + 31 = 2341. So 2341 is the required number.