Non-repeating, non-terminating decimals.
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'pi' and 'e' both fit that description.
The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.
They are the universal set: every number that doesn't fit in the circles in the venn diagram.
An infinite amount.
Because the mode is 5, we know at least two of the numbers are 5. Because the median is 12 and we have five numbers, we know one of them is 12. Because the range is 10 and the smallest number we know so far is 5, we'll try 15 for a fourth number. This gives us: 5, 5, 12, 15 The mean is 10, so we know the sum of all five numbers is 50. The sum of the four numbers we have so far is 5+5+12+15 = 37. Thus, the fifth number is 50-37 = 13. That gives us 5, 5, 12, 13, 15. These five numbers fit all the criteria.