First, we need to clarify the condition in the problem: the sum of two numbers is 16, and the difference between the two numbers is 6. Based on these conditions, we can say that these two numbers are respectively
x and y. According to the problem description, we can list the following equations:
The sum of the two numbers is 16, which is
x plus y is equal to 16.
The difference between the two numbers is 6, which is 6
x−y=6.
By solving this system of equations, we get
x=9 and y=7. So the product of these two numbers is
9 x 7 = 63
six, nine 9 + 6 = 15 (sum) 9 - 6 = 3 (difference) 9 x 6 = 54 (product)
six, seven 7 + 6 = 13 (sum) 7 - 6 = 1 (difference) 7 x 6 = 42 (product)
You multiply them. Addition = sum Subtraction = difference Multiplication = product Division = quotient
To get the product, multiply the first number by the second. To get the sum, add the second number to the first. To get the difference, subtract the smaller number from the larger.
26
8
The numbers are zero and 5. Their product is zero.
The two numbers must be 6 and 9, as 6 + 9 = 15 and theer is a difference of 3 between 6 and 9. The product of 6 and 9 = 54.
Sum: 16 Product: 48 Difference: 8 Quotient: 3
The numbers are 13 and 8 The product is 104
when you add numbers, you get a sum. when you subtract numbers, you get a difference. (also in multiplication it's product, and in division is quotient.)
Sum of squares? Product?