There are no two real numbers that will add to -9 and multiply to 81. Using complex numbers, the two numbers are: (-9/2 + i9/2√3) and (-9/2 - i9/2√3)
The numbers, when summed, are 75, 77, 79 and 81.
Three consecutive integers: x, (x+1), (x+2)Sum: x + (x+1) + (x+2) = 81x + x + 1 + x + 2 = 813x + 3 = 813x = 78x = 26The numbers are 26, 27, 28.=================Check:26 + 27 + 28 = 81 yay!
8X8=64, and 9X9=81; so I would say 8 and 9.
They are consecutive square numbers: 12 22 32 42 .... etc
11 + 12 + 13 + 14 + 15 + 16 = 81
25, 27, 29
11, 12, 13, 14, 15 and 16.
The numbers are 11, 12, 13, 14, 15 and 16.
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Consecutive numbers, by definition, don't differ by 17. It would have to be something like consecutive square numbers (64 and 81).
36 and 45
The numbers are 81, 82, 83, 84 and 85.
Let the second number be x, then the three consecutive numbers are x-1, x, x+1, and their sum is: (x-1) + x + (x+1) = 81 3x = 81 x = 27 So the three numbers are 27-1, 27, 27+1 = 26, 27, 28
81
25 (25+27+29=81)
The numbers are 81, 82 and 83.