Let the second number be x, then the three consecutive numbers are x-1, x, x+1, and their sum is:
(x-1) + x + (x+1) = 81
3x = 81
x = 27
So the three numbers are 27-1, 27, 27+1 = 26, 27, 28
81 + 83 = 164
There are four consecutive odd integers: 81, 83, 85 and 87.
The numbers are 81, 82, 83, 84 and 85.
To find the sum of the first 81 odd numbers, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (2a + (n-1)d), where n is the number of terms, a is the first term, and d is the common difference. In this case, n = 81, a = 1 (first odd number), and d = 2 (since the difference between consecutive odd numbers is 2). Plugging these values into the formula, we get: S81 = 81/2 * (2(1) + (81-1)2) = 81/2 * (2 + 160) = 81/2 * 162 = 6561. Therefore, the sum of the first 81 odd numbers is 6561.
There are no three consecutive whole numbers which multiply to 81.3x4x5=604x5x6=120The nearest we can get to 81 by using 'consecutive' decimal numbers to 4 places of decimals is to use the sequence:3.4038 x 4.4038 x 5.4038 = 81.01253However, most people would argue that the expression 'consecutive numbers' means 'consecutive whole numbers.'If this is so, then 'numbers' such as 3.4038 are disallowed.But if the question should be "Which number multiplied by itself three time comes to 81? then an answer could worked out in this way ....Use the number 3.Multiply 3 by itself, but do this once. The answer is 9 (i.e. 3x3)Then multiply the answer again by 3. This will be the second time you have performed the multiplication. The answer is 27 (9x3).Then multiply by 3 a third time, and the answer will be 81 (27x3)Even so, the usual way to calculate three multiplied by itself 3 times is to set it out like this: 3x3x3. But this gives the answer 27, which is not what we are looking for in the question!
The numbers are 81, 82 and 83.
25 (25+27+29=81)
27,28,29The sum of which is 84.
35,13,33
The numbers are 81, 82 and 83. Also, 80, 82 and 84
11 + 12 + 13 + 14 + 15 + 16 = 81
Three consecutive integers: x, (x+1), (x+2)Sum: x + (x+1) + (x+2) = 81x + x + 1 + x + 2 = 813x + 3 = 813x = 78x = 26The numbers are 26, 27, 28.=================Check:26 + 27 + 28 = 81 yay!
Since they are consecutive and three, they must be in their 20s (81/3 = 20 with a rest 0f 21) So its just finding out which 3 integers sum up to 21 ... and thats ..... 6,7,8
The numbers are 11, 12, 13, 14, 15 and 16.
x + (x+2) + (x+4) = 249 3x+6=249 3x=243 x=81 81, 83, and 85
25, 27, 29
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