The square root of 9604 is 98.
√98 = 7√2 = 9.9
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Well, darling, 7 square root 2 squared is just 98. You see, when you square a number, you multiply it by itself. So, 7 times 7 is 49, and then you multiply that by 2 to get 98. Math can be a piece of cake if you just give it a whirl!
square root 2 times square root 3 times square root 8
98 is 49 times 2 so the square root of 98 is the square root of 49 times the square root of 2. But the square root of 49 is 7 , so the answer is 7 times the square root of 2.
No because the square root of 98 is 7 times the square root of 2
The simplified square root of 98 is: ±9.9 or ±10
No. If the square root of 98 was an integer, 98 would be a perfect square.
The square root of 9604 is 98.
√98 ~= 9.899
49
49
It is 98 because 98*98 = 9604
9.899494936611665It is: 7 times square root of 2± 9.899495
2.83 to the nearest hundredth.
Expressed as a surd, sqrt(98) + sqrt(2) = 8 sqrt(2).