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Expressed as a surd, sqrt(98) + sqrt(2) = 8 sqrt(2).

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14y ago

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Can you write the square root of 98 as 6 times the square root of 3?

No because the square root of 98 is 7 times the square root of 2


Square root of 98 divided by square root of 2?

49


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√98 + √8. This can be expressed as, √98 + √8 = √(2 x 49) + √(2 x 4) The square root of 49 is 7, and the square root of 4 is 2. So the expression now becomes :- 7√2 + 2√2 = (7 + 2)√2 = 9√2. As √2 = 1.41421 (5dp) then the answer is :- 9 x 1.41421 = 12.72792 Use of a calculator gives 9.89949 + 2.82843 = 12.72792


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sqrt(98) = sqrt( 2 x 49(_ = sqrt(2) X sqrt(49) = sqrt(2) X 7 usually written as 7sqrt(2) (Surd form) Numerically the answer is 9,899494937.....


What is the square root of 2 plus the square root of 2 in square root form?

The square root of 2 plus the square root of 2 is equal to twice the square root of 2, therefore the correct answer is: 2(√2) or √8


What is 5 times the square root of 2 plus the square root of 3 times the quantity of the square root of 2 plus 2 times the square root of 3?

if you take out the word ''quantity'' your answer is 25.02725024


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What is the square root 2 plus 3 square root 5 Times Square root 2 minus square root 7?

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