Also 18 and 27.
Wiki User
∙ 8y agoWiki User
∙ 9y agoThe numbers 9 and 54.
LCM/GCF = 54/9 = 6 So you require two factors of 6 such that their maximum is the smallest. Therefore, rather than 1 and 6, you select 2 and 3. The two numbers are GCF*2 and GCF*3, that is 18 and 27.
54108, because 54108*1=54108. Usually (in fact always) LCM is between two or more numbers. So this question shouldn't even be answerable. Next time remember... TWO OR MORE NUMBERS FOR LCM!
Every time I've seen a similar question, one of the numbers is a multiple of the other and the two numbers satisfy the requirements. 9 and 54 have a GCF of 9 and an LCM of 54. Another way to solve it: The product of the GCF and LCM of two numbers is equal to the product of the two numbers. 9 x 54 = 486. Now you're looking for another factor pair of 486 that satisfy those requirements. 18 and 27 do that.
Gcf = 54 lcm = 108
27 and 54, respectively.
For the given set 3 and 54, the GCF is 3 and the LCM is 54.
3 and 54, respectively.
The LCM is 1890 The GCF is 6
The LCM is 270. The GCF is 3.
The two numbers 18 and 27. Factorising the lcm and gcf gives: 54 = 2 × 3³ 9 = 3² There must be 3² in both numbers, but there must be a 3³ and a 2 which must appear in the prime factorisations of the two numbers. Putting a 2 with one 3² and a 3 with the other 3² leads to the two numbers: 2 × 3² = 18 3 × 3³ = 3³ = 27 as the two smallest numbers with gcf=9 and lcm=54. The other distribution of both 2 and 3 with one 3² results in the two number 3² = 9 and 2 × 3³ = 54, the latter of which is larger than both the 18 and 27 previously found.
54 and 56
The LCM of the given two numbers is 918