To find two numbers with a greatest common factor (GCF) of 9 and a least common multiple (LCM) of 54, we can use the relationship between GCF, LCM, and the product of two numbers. The product of two numbers is equal to the product of their GCF and LCM. So, if GCF is 9 and LCM is 54, the product of the two numbers is 9 * 54 = 486. To find the two numbers, we need to find a pair of factors whose product is 486 and whose GCF is 9. The numbers that meet these criteria are 27 and 18.
Well, honey, the two numbers you're looking for are 27 and 54. Their greatest common factor is 9 because that's the largest number that divides both of them evenly. And their least common multiple is 54 because, well, that's what you get when you multiply them together. Math can be sassy too, you know!
Oh, dude, so the greatest common factor (GCF) is like the BFF of numbers, right? And the least common multiple (LCM) is like the party they both get invited to. So, if the GCF is 9, it's like saying, "Hey, I can fit into both of your circles," and the LCM is 54, which is like the big party where they all hang out together. So, the two numbers would be 27 and 54.
what is the gcf of 24 and 54 is : 6
54
=The Two numbers are 41 and 13.=
The GCF is 27.
To find the greatest common factor (GCF) of 18, 54, and 90, we first need to find the prime factorization of each number. The prime factorization of 18 is 2 * 3^2, the prime factorization of 54 is 2 * 3^3, and the prime factorization of 90 is 2 * 3^2 * 5. To find the GCF, we identify the common prime factors among the numbers, which are 2 and 3^2. Therefore, the GCF of 18, 54, and 90 is 2 * 3^2, which equals 18.
LCM/GCF = 54/9 = 6 So you require two factors of 6 such that their maximum is the smallest. Therefore, rather than 1 and 6, you select 2 and 3. The two numbers are GCF*2 and GCF*3, that is 18 and 27.
54108, because 54108*1=54108. Usually (in fact always) LCM is between two or more numbers. So this question shouldn't even be answerable. Next time remember... TWO OR MORE NUMBERS FOR LCM!
Every time I've seen a similar question, one of the numbers is a multiple of the other and the two numbers satisfy the requirements. 9 and 54 have a GCF of 9 and an LCM of 54. Another way to solve it: The product of the GCF and LCM of two numbers is equal to the product of the two numbers. 9 x 54 = 486. Now you're looking for another factor pair of 486 that satisfy those requirements. 18 and 27 do that.
Gcf = 54 lcm = 108
27 and 54, respectively.
For the given set 3 and 54, the GCF is 3 and the LCM is 54.
3 and 54, respectively.
The LCM is 1890 The GCF is 6
The LCM is 270. The GCF is 3.
The LCM of the given two numbers is 918
27 and 54, among others.
The two numbers 18 and 27. Factorising the lcm and gcf gives: 54 = 2 × 3³ 9 = 3² There must be 3² in both numbers, but there must be a 3³ and a 2 which must appear in the prime factorisations of the two numbers. Putting a 2 with one 3² and a 3 with the other 3² leads to the two numbers: 2 × 3² = 18 3 × 3³ = 3³ = 27 as the two smallest numbers with gcf=9 and lcm=54. The other distribution of both 2 and 3 with one 3² results in the two number 3² = 9 and 2 × 3³ = 54, the latter of which is larger than both the 18 and 27 previously found.