Q: What two numbers have a sum of 8 and a product of 15?

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15 + 1 = 16, and 15 - 1 = 14, so the two numbers are 15 and 1.

Let the two numbers be 'm' & 'n' Sum = m + n = -9 Product is mn = -90 Hence m = -90/n Substitute -90/n + n = -9 Multiply through by 'n' -90 + n^2 = - 9n n^2 + 9n - 90 = 0 It is now in quadratic form ; factor (n + 15)(n - 6) = 0 n = -15 & n = 6

A product is the answer when you multiply two or more numbers. 5x3=15 so 15 is the product. 21x2x1=42 so 42 is the product.

The numbers are -16 and -15.

8 , and 7. x+y=15 >> x=-y+15 x*y=56 >> y*(-y+15)=56 , then solve for y , put y back into either equation for x.

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The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56

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