3 and 5
15 + 1 = 16, and 15 - 1 = 14, so the two numbers are 15 and 1.
Let the two numbers be 'm' & 'n' Sum = m + n = -9 Product is mn = -90 Hence m = -90/n Substitute -90/n + n = -9 Multiply through by 'n' -90 + n^2 = - 9n n^2 + 9n - 90 = 0 It is now in quadratic form ; factor (n + 15)(n - 6) = 0 n = -15 & n = 6
A product is the answer when you multiply two or more numbers. 5x3=15 so 15 is the product. 21x2x1=42 so 42 is the product.
The numbers are -16 and -15.
8 , and 7. x+y=15 >> x=-y+15 x*y=56 >> y*(-y+15)=56 , then solve for y , put y back into either equation for x.
3 & 15
3 and 12
12 and 3
The two numbers are 8 and 15
15 and 3
Zero and 15.
They're 5 and 15.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
The two numbers that have a sum of 23 and a product of 120 are 15 and 8. This can be verified since 15 + 8 equals 23 and 15 × 8 equals 120.
10 and 15
15 and 2
14 and 11