parrell
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
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x + 2y = 7 2y = -x + 7 y = -(x-7)/2 => -x/2 + 7/2 2x - y = 7 -y = -2x + 7 y = 2x + 7 Since -1/2 is the negative reciporical of 2, the slopes of these equations are perpendicular. Therefore, these two lines are perpendicular.
If this is related to coordinate geometry then the shading refers to the areas on the graph that satisfy the given inequations i.e if y>=2x+3 and y>= -2x+3 then the areas above both lines would be shaded.
It is (2x +y + 3)*(2x - y - 3).
parallel
They are parallel lines
Straight lines.
y-2x=3 -y -y -2x=3-y -3 -3 -2x-3=-y /-1 /-1 2x+3=y y=2x and y=2x+3 have the same slope of 2, so they are parallel. Hope this helps! ;D
They are parallel lines with a vertical separation of 1.
As stated these are not lines, but just a collection of algebraic terms. If we change them to y=2x and y=2x-1, then on a graph of y versus x, these are parallel lines separated by vertical distance of 1.
If the second equation is: y minus 2x equals 3, then:y - 2x = 3 ⇒ y = 2x + 3 and it is parallel to y = 2x.Otherwise (with with missing operator as "plus", "multiply" or "divide"), the lines are neither parallel nor perpendicular.
If you mean y = 2x and y = 2x-1 then they are parallel lines because they have the same slope.
If two lines have the same slope (ie. they rise or fall at the same angle) they are parallel.With lines, the number before the x determines the slope. So as long as your line has a 2x term, and is written in the same form as y = 2x + 3, it will be parallel.Therefore,y = 2x + 7y = 2x +5556y = 2x - 3y = 2x - 0.7561... are all parallel lines to y = 2x + 3
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
Assuming you want to find the point at which those two lines intercept: We are told: y - 2x = -3 ∴ y = 2x - 3 We are also told: 4x - y = -1 ∴ 4x - (2x - 3) = -1 ∴ 2x - 3 = -1 ∴ 2x = 2 ∴ x = 1 Now we know the value of x, and can plug it back into either of the original equations to find y: y = 2x - 3 ∴ y = 2 - 3 ∴ y = -1 So the lines defined by these equations intercept at the point (1, -1).
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