2x + 2 = 4x -1 2x = 3 x = 1.5
4x + 1 = 2x + 5 Subtract '1' frp, bpth sides Hence 4x = 2x + 4 Subtract '2x' from botbh sides 2x = 4 Divide both sides by '2' x = 2 The answer!!!!!!
The two lines are: 2x+4y=2 4x+2y=5 Le't write them in slope intercept form 4y=-2x+2 or y=-1/2+1/2 AND 2y=-4x+5 or y=-2x+5/2 Now we use the fact the parallel lines have the same slope. One line here has slop =1/2 and the other has -2. Next if lines are perpendicular the product of the slopes is -1. This is not the case here either. So the answer is NEITHER!
3+4x+2-2x=2x+5
-2x = -4x + 24 -2x + 4x = 24 2x = 24 x = 24/2 x = 12
neither
(2x - 3)(4x + 9)(2x + 3) = (2x - 3)(2x + 3)(4x + 9) = [(2x)^2 - (3^2)](4x + 9) = (4x^2 - 9)(4x + 9) = (4x^2)(4x) + (4x^2)(9) - (9)(4x) - (9)(9) = 16x^3 + 36 x^2 - 36x - 81
4x + 2 + 2x - 2x = 14 4x = 14 - 2 4x = 12 x = 3
2x
4x^2
2 - 4x - 2x + 4 = 6 - 6x
2x + 2 = 4x -1 2x = 3 x = 1.5
4x + 1 = 2x + 5 Subtract '1' frp, bpth sides Hence 4x = 2x + 4 Subtract '2x' from botbh sides 2x = 4 Divide both sides by '2' x = 2 The answer!!!!!!
4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).
As written, that's 2(x - 6) You may have meant 4x^2 - 2x - 12 which would be 2(2x + 3)(x - 2)
The two lines are: 2x+4y=2 4x+2y=5 Le't write them in slope intercept form 4y=-2x+2 or y=-1/2+1/2 AND 2y=-4x+5 or y=-2x+5/2 Now we use the fact the parallel lines have the same slope. One line here has slop =1/2 and the other has -2. Next if lines are perpendicular the product of the slopes is -1. This is not the case here either. So the answer is NEITHER!
Those two statements are linear equations, not lines. If the equations are graphed, each one produces a straight line. The lines intersect at the point (-1, -2).