Straight lines.
2x + 2 = 4x -1 2x = 3 x = 1.5
4x + 1 = 2x + 5 4x + 1 - 2x = 2x + 5 - 2x 2x + 1 = 5 2x + 1 - 1 = 5 - 1 2x = 4 2x/2 = 4/2 x = 2
The two lines are: 2x+4y=2 4x+2y=5 Le't write them in slope intercept form 4y=-2x+2 or y=-1/2+1/2 AND 2y=-4x+5 or y=-2x+5/2 Now we use the fact the parallel lines have the same slope. One line here has slop =1/2 and the other has -2. Next if lines are perpendicular the product of the slopes is -1. This is not the case here either. So the answer is NEITHER!
3+4x+2-2x=2x+5
-2x = -4x + 24 -2x + 4x = 24 2x = 24 x = 24/2 x = 12
neither
(2x - 3)(4x + 9)(2x + 3) = (2x - 3)(2x + 3)(4x + 9) = [(2x)^2 - (3^2)](4x + 9) = (4x^2 - 9)(4x + 9) = (4x^2)(4x) + (4x^2)(9) - (9)(4x) - (9)(9) = 16x^3 + 36 x^2 - 36x - 81
4x + 2 + 2x - 2x = 14 4x = 14 - 2 4x = 12 x = 3
4x^2
2 - 4x - 2x + 4 = 6 - 6x
2x + 2 = 4x -1 2x = 3 x = 1.5
4x + 1 = 2x + 5 4x + 1 - 2x = 2x + 5 - 2x 2x + 1 = 5 2x + 1 - 1 = 5 - 1 2x = 4 2x/2 = 4/2 x = 2
4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).
As written, that's 2(x - 6) You may have meant 4x^2 - 2x - 12 which would be 2(2x + 3)(x - 2)
To determine the type of lines represented by the equations ( y = 2x + 4 ) and ( y = 2x + 5 ), we can observe their slopes. Both equations have the same slope of 2, indicating that they are parallel lines. Since parallel lines never intersect, they will never meet at any point on the graph.
The two lines are: 2x+4y=2 4x+2y=5 Le't write them in slope intercept form 4y=-2x+2 or y=-1/2+1/2 AND 2y=-4x+5 or y=-2x+5/2 Now we use the fact the parallel lines have the same slope. One line here has slop =1/2 and the other has -2. Next if lines are perpendicular the product of the slopes is -1. This is not the case here either. So the answer is NEITHER!
Those two statements are linear equations, not lines. If the equations are graphed, each one produces a straight line. The lines intersect at the point (-1, -2).