Because they're not physically meaningful. For example, if you have an equation which tells you how many widgets you need to make to maximize your profit and it tells you could could either make 12 or -4, you're going to have a hard time making negative four widgets.
As the answer by P Torquemada states, it may not be physically meaningful. But in principle, you must really analyze the situation in each particular case. Sometimes both solutions are meaningful; sometimes there are obvious reasons why you should reject a negative solution, or a solution that is less than (or greater than) a certain number.
It is usually because the variable in question, for example, length or mass, cannot have a negative value.
If the discriminant is positive, as in this case, there are two real solutions.Also: * If the discriminant is zero, there is one real solution, considered to be a "double solution" because of the way polynomials are factored. * If the discriminant is negative, there are two complex solutions, which are complex and non-real.
Two complex solutions.
Two
By calculating the discriminant of the equation and if it's negative the equation will have no solutions
irreducible polynomial prime...i know its the same as irreducible but on mymathlab you would select prime
The negative solutions are often discard because they have no real meaning in the real world, for example, you can not have -6 apples, it just doesn't make sense.
Because in real world problems, you cannot have answers such as "-3 people", "-4.56 minutes", "a shoe size of -9" etc... It is not logical.
They are not always discarded. However, there are some measures that cannot be negative: such as your age or mass or the length of a rectangular field. The reason for rejecting a negative solution depends on the context of the question.
true
No.
Polynomials cannot have negative exponent.
If the discriminant is positive, as in this case, there are two real solutions.Also: * If the discriminant is zero, there is one real solution, considered to be a "double solution" because of the way polynomials are factored. * If the discriminant is negative, there are two complex solutions, which are complex and non-real.
The numbers can have a positive or negative sign.
As stated in the attached link, there are three possible discriminant conditions: Positive, Zero, or Negative. If the discriminant is negative, there are no real solutions but there are two imaginary solutions. So, yes there are solutions if the discriminant is negative. The solutions are imaginary, which is perfectly acceptable as solutions.
just add the negative of the polynomial, that is the same as subtracting it. For example, x^2+2x is a poly, the negative is -x^2-2x. So if we want to subtract x^2+2x from another poly, we can add the negative instead.
There are many possible answers. 1 and 2280 is one pair of integers, 2 and 1140 is another, 3 and 760 yet another. And then there are solutions involving the same pairs of numbers but both negative, non-integer solutions, etc.
Two complex solutions.