three things:
1) that the value of 4 is equal to the value of 4.
2) you did not obtain any revealing information.
3) your strategy for solving that system of equations was not good.
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If you mean: 6x-3y = -33 and 2x+y = -1 Then solving the simultaneous equations by substitution: x = -3 and y = 5
Solving linear systems means to solve linear equations and inequalities. Then to graph it and describing it by statical statements.
Find values for each of the unknown variables (or at least as many as is possible for the system) that satisfy all the equations.
No. At least, it can't have EXACTLY 3 solutions, if that's what you mean. A system of two linear equations in two variables can have:No solutionOne solutionAn infinite number of solutions
Finding a set of value for the set of variables so that, when these values are substituted for the corresponding variables, all the equations in the system are true statements.