The length is 32. Since an isosceles triangle is symmetrical, the height divides it into two right triangles. The hypotenuse of one of these triangles is 34, one of the legs is 30 (the height), and the other leg is half of the base, which we'll call x. Using the Pythagorean Theorem, we know x^2+30^2=34^2, or x^2+900=1156. This gives us x^2=256, or x=16 (it could also be -16, but this is absurd because it's a length). We said x was half the base, so the base itself is 2x=2*16=32.
An isosceles triangle is in effect two right angled triangles joined together and in this case they have bases of 5 units and heights of 2 units so use Pythagoras' theorem to find the hypotenuse which will be the length of one of the equal legs of the isosceles triangle:- 52+22 = 29 and the square of this is about 5.385164807 or 5.385 to 3 dp
Work out each figure separately then add them together: Area of a trapezoid = 0.5*(sum of parallel bases)*height Area of a rectangle = length*height
2*Area of Bases + Perimeter of base*Length.
A cylinder is a tree-dimensional figure with two parallel bases bounded by congruent circles and a curved lateral surface that connects the circles. The height, h, of a cylinder is the length of any perpendicular segment drawn from a point on the base to the plane containing the other base. A cylinder is a right cylinder if the segment joining the centers of the bases is perpendicular to the planes of the bases. Otherwise, the cylinder is oblique. If a right cylinder has a height h and a base with radius r, then the lateral area L.A. is given by the formula: L.A. = 2(pi)(r)(h) The surface area S.A. is given by the formula: S.A. = L.A. + 2(pi)(r^2). Thus, the area of the cylinder's base is (pi)(r^2).
The volume of a three-dimensional figure is the amount of space it encloses. The volume V of a triangular prism is the product of the area B of a base and the height h of the prism. (The bases are triangles. In a special case of a right triangular prism the bases are right triangles)
congruent means equivalent. An equilateral triangle has 3 of the same sides, not two. Isosceles triangles can have 2 or 3 of the same length sides. Congruent isosceles triangles are impossible.I agree with most of the above answer but not the last sentence. It is possible to have congruent isosceles triangles. If the legs (sides) of triangle 1 are the same length as the legs of triangle 2, and the bases (third side) of the two triangles are the same length then the two isosceles triangles will be congruent.So the answer to the question is: yes, a congruent triangle can have two same length sides.
If you draw another altitude parallel to the height (the side which is perpendicular to the bases) of the trapezoid, you can see that a right triangle is formed.In this triangle the hypotenuse length is 17 in, and the base length equals to 28 - 16 = 12 in. From the Pythagorean theorem, height length = √(17 - 12) ≈ 12 in.Or find the measure of the angle (call it A) opposite to the height such as:cos A = 12/17A = cos-1 (12/17) ≈ 45⁰, which tells us that this right triangle is an isosceles triangle.Therefore, the height is (congruent with base) 12 inches long
Sometimes triangular prisms have isosceles triangle bases. It is the most common, but they don't always have isosceles triangles.
An isosceles triangle is in effect two right angled triangles joined together and in this case they have bases of 5 units and heights of 2 units so use Pythagoras' theorem to find the hypotenuse which will be the length of one of the equal legs of the isosceles triangle:- 52+22 = 29 and the square of this is about 5.385164807 or 5.385 to 3 dp
No, it is not.
No its parallel bases can never be equal in length. But if it is in the form of an isosceles trapezoid then its slanted sides are equal in length.
22 mertes. And the trapezoid does not have to be isosceles.
28.5
28.5
An equilateral triangle with 3 equally sized isosceles triangles connected to it by their bases
23.5 Units
25.5 units