x = 8y = 6(5x8) + (3x6) = 58(5x8) - (3x6) = 22
What is the area bounded by the graph of the function f(x)=1-e^-x over the interval [-1, 2]?
y=1/3x+3
It is 1.2164
y = 8 - 2*x
x = 8y = 6(5x8) + (3x6) = 58(5x8) - (3x6) = 22
10x4 5x8 20x2 40x1 2x2x2x5
f(f(x)) = f(x). Only if f is 1-1 then we have a solution f(x)=x.
Yes.
No, but cos(-x) = cos(x), because the cosine function is an even function.
f(x) = 2*(x-3)*(x+2)/(x-1) for x ≠1
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
Yes. Think of y as being a function of x. y = f(x) = x2 + 1
y < 1
X - Y^2 = 1 - Y^2 = - X + 1 Y^2 = X - 1 Y = (+/-) sqrt(X - 1) now, X is represented as a function of Y. Function values are generally Y values.
3
exactly...