f(x) and g(x) are just names of generic functions - they could be anything. In any specific case, where they intersect depends on how the functions are defined. In general, to find out where they intersect you can solve for:
f(x) = g(x)
Replacing the corresponding expressions for each function of course.
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If the two at the end of these are exponents, like x^2, then these graphs would be reflections across the x-axis. Their graphs would be two parabolas. f(x) pointing up, and g(x) pointing down.
That depends on the value of x. You can think of those two expressions as being linear functions: f(x) = -3x - 6 g(x) = x - 2 To find the point at which they intersect (where f(x) = g(x)), we simply have to declare them as being equal and solve for x: if f(x) = g(x) then: -3x - 6 = x - 2 -4x = 4 x = -1 So the two functions intersect at the point where x = -1. If you plug that value into either function, you'll find that they return the value -3. This tells ups that these functions describe two lines that intersect at the point (-1, -3). Given that the coefficient of our first function, "f" has a lower value than the function "g", we know that when the x value is greater than that of their point of intersection, "g" will return a greater value. Before our point of intersection, "f" will return a greater value. So in answer to your original question, we can say: if x < -1: yes if x ≥ -1: no
G(F(x)) =~F(x) = and G(x) = 1F(x) = + 1 and G(x) = 3xF(x) = x + 1 and G(x) =orF(x) = 3x and G(x) = + 1-F(x) = x+ 1 and G(x) =G(F(x)) = x4 + 3~F(x) = x and G(x) = x4F(x) = x + 3 and G(x) = x4F(x) = x4 and G(x) = 3orF(x) = x4 and G(x) = x+ 3-It's F(x) =x4 andG(x) = x+ 3G(F(x)) =4sqrt(x)F(x) = sqrt(x) and G(x) = 4x
(f+g)(x) = 4x + 8 + 5x -6 => (f+g)(x) = 9x + 2
If f(x)=2z^2+5 and g(x)=x^2-2, fine (f-g)(x)