2
Re-write it with a root. If the power of the expression is less than 1, for example x1/3, the expression could be rewritten as cube root of x.
1
In general, not usually.The square root of an irrational number is always irrational.The square root of a rational number is usually irrational, but not always. You can tell by this test:If both the numerator and denominator of the number expressed as a simplified fraction are perfect square numbers (a number whose square root is a whole number), then the square root of the whole fraction will be rational.Example: Sqrt(4) =2 (the positive one). Sqrt(1) = 1. Both are perfect squares.So sqrt(1/4) = sqrt(1)/sqrt(4) = 1/2. Another one: sqrt(4/9) = 2/3.
also -1
The number 27 has a cube root of 3, which is 2 (the smallest prime) plus 1.
-21 + 1.7320508i1 - 1.7320508i
[-1+sqrt(3)]1/4
You do. The other two are complex numbers, of interest only tomathematicians and engineers, and usually not listed.For example, the three cube roots of 8 are:2-1 + i sqrt(3)-1 - i sqrt(3)
Re-write it with a root. If the power of the expression is less than 1, for example x1/3, the expression could be rewritten as cube root of x.
The expression ( 18^{\frac{1}{2}} ) represents the square root of 18. Therefore, the equivalent radical expression is ( \sqrt{18} ), which can also be simplified to ( 3\sqrt{2} ) since ( 18 = 9 \times 2 ).
Yes, a number can have more than one cube root, but the situation varies depending on whether we are considering real or complex numbers. In the realm of real numbers, every non-zero number has one real cube root. However, in the context of complex numbers, every number has three distinct cube roots due to the properties of complex exponentiation. For example, the cube roots of 1 are 1, ( \frac{-1 + \sqrt{3}i}{2} ), and ( \frac{-1 - \sqrt{3}i}{2} ).
It is easier to describe using an actual example. Say you have an expression x/sqrt(2). Then multiply by sqrt(2)/sqrt(2) (which is of course equal to 1 and we know that anything multiplied by 1 stays the same. This will get rid of the radical on the bottom. So the expression becomes x/sqrt(2) * sqrt(2)/sqrt(2) = [x*sqrt(2)]/2 where * means multiply
YES!!!! sqrt(x) = x^(0.5) = x^(1/2) It is just mathematical convenience, which expression you choose. NB Cube Root curt(x) = x^(0.333....) = x^(1/3) Fourth root 4rt(x) = x^(0.25) = x^(1/4) et.seq.,
Yes, but it involves the square root of -1. sqrt (-X) = sqrt (X) * sqrt(-1)
-1X-1X-1=-1 therefore cube root of -1 = -1
It will depend on where you put your parentheses. Root 7 -( 1/root 7) is different from (root 7-1)/root 7. * * * * * True, but a more helpful answer: [sqrt(7) - 1]/[sqrt(7) + 1] - [sqrt(7) + 1]/[sqrt(7) - 1] Multiplying the numerator and denominator of the first fraction by [sqrt(7) - 1] and the second fraction by [sqrt(7) + 1] = [sqrt(7) - 1]2/[7 - 1] - [sqrt(7) + 1]2/[7 - 1] =[7 - 2*sqrt(7) + 1]/6 - [7 + 2*sqrt(7) + 1]/6 = 16/6 = 8/3
1