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Osbaldo Fadel

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Q: Which expression is a cube root of -1 + i sqrt 3?
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Related questions

What is the cube root of -8 with complex answers?

-21 + 1.7320508i1 - 1.7320508i


Which expression is a fourth root of negative 1 plus sqrt3?

[-1+sqrt(3)]1/4


Why dont you have three answers for cube root?

You do. The other two are complex numbers, of interest only tomathematicians and engineers, and usually not listed.For example, the three cube roots of 8 are:2-1 + i sqrt(3)-1 - i sqrt(3)


How do you write an expression in radical form?

Re-write it with a root. If the power of the expression is less than 1, for example x1/3, the expression could be rewritten as cube root of x.


How can we rationalize the divisor in division of radicals?

It is easier to describe using an actual example. Say you have an expression x/sqrt(2). Then multiply by sqrt(2)/sqrt(2) (which is of course equal to 1 and we know that anything multiplied by 1 stays the same. This will get rid of the radical on the bottom. So the expression becomes x/sqrt(2) * sqrt(2)/sqrt(2) = [x*sqrt(2)]/2 where * means multiply


Is raising a number to the power of 0.5 the same as square root?

YES!!!! sqrt(x) = x^(0.5) = x^(1/2) It is just mathematical convenience, which expression you choose. NB Cube Root curt(x) = x^(0.333....) = x^(1/3) Fourth root 4rt(x) = x^(0.25) = x^(1/4) et.seq.,


Can a value in a square root be negative?

Yes, but it involves the square root of -1. sqrt (-X) = sqrt (X) * sqrt(-1)


What is the cube root of 1?

-1X-1X-1=-1 therefore cube root of -1 = -1


What is the solution is the of this equation root 7- 1 divide by root 7 plus 1 - root 7 plus 1 divide by root 7 - 1?

It will depend on where you put your parentheses. Root 7 -( 1/root 7) is different from (root 7-1)/root 7. * * * * * True, but a more helpful answer: [sqrt(7) - 1]/[sqrt(7) + 1] - [sqrt(7) + 1]/[sqrt(7) - 1] Multiplying the numerator and denominator of the first fraction by [sqrt(7) - 1] and the second fraction by [sqrt(7) + 1] = [sqrt(7) - 1]2/[7 - 1] - [sqrt(7) + 1]2/[7 - 1] =[7 - 2*sqrt(7) + 1]/6 - [7 + 2*sqrt(7) + 1]/6 = 16/6 = 8/3


If root -1 is i what is root -2?

1


What is the reciprocal of negative square root 3 plus square root 6 you?

It is sqrt(3)*[1 + sqrt(2)]/3 or [1 + sqrt(2)]/sqrt(3)


What is the square root of 001?

Sqrt(001) = sqrt(1) = ±1