Well, honey, if you're looking for a function that passes through the points (2, 15) and (3, 26), you're talking about a linear function. The slope of this function would be 11 (rise of 11 over run of 1), so the equation would be y = 11x + b. To find the y-intercept, plug in one of the points, let's say (2, 15), and solve for b. So, the function that passes through those points is y = 11x + 4.
Points: (3, 15) and (5, 9) Slope: -3
If the points are (1,5) and (0,0) y = 5x
If you mean points of (-5, 0) and (10, 9) then the slope is 3/5 and the straight line equation is 5y = 3x+15
If you mean points of (20, 15) and (48, 36) then its slope is 3/4 and equation 4y = 3x And the equation of (-4, -3) with a slope of 3/4 is also 4y = 3x
-15-16/-7-19=-1/26
Points: (0, 5) and (10, -15) Slope: -2
Points: (3, 15) and (5, 9) Slope: -3
The slope of the line that passes through the points (3,15) and (5,9), is -3; use the formula change in Y-axis/change in X-axis.
If the points are (1,5) and (0,0) y = 5x
slope is =( 9-15 )/ (5-3) = -6/2 = -3
The idea is to divide (difference in y-coordinates) by (difference in x-coordinates). If you mean points of (-5, 4) and (15, -4) then the slope works out as -2/5
(- 2, 15) and (- 8, - 5)m = Y2 - Y1/X2 - X1m = - 5 - 15/- 8 - (- 2)m = 10/3=======
188
If you mean points of (-5, 0) and (10, 9) then the slope is 3/5 and the straight line equation is 5y = 3x+15
m = (Y2-Y1)/(X2-X1) 75-60/72-60 = 15/12 = 5/4
If you mean points of (20, 15) and (48, 36) then its slope is 3/4 and equation 4y = 3x And the equation of (-4, -3) with a slope of 3/4 is also 4y = 3x
Somewhat. You get 1 Karma every 10 passes you buy. And every 5 Karma (5, 10, 15, 20, etc) you have, you get a free pass.