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Q: Using the point slope formula what is the equation of the line that passes through the points 15 and 00?

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Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.

Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5

If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x

Points: (-3, -4) and (6, -1) Slope: 1/3 Equation: 3y = x-9

Points: (6, -3) and (-4, -9) Slope: 3/5 Equation: 5y = 3x-33

Related questions

Write the equation of the line that passes through the points (3, -5) and (-4, -5)

y = 0

The equation for the given points is y = x+4 in slope intercept form

If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6

It is y = 2.

Y= -3x + 8

y = 5x or f(x) = 5x, depending on your notation

Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.

Answer this question…y = 2x + 6

In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.

Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5

If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x

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