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Which has the larger perimeter a 16-foot by 26-foot rectangle or a 20 foot square?
Wiki User
∙ 13y ago
Perimeter of [ 16 x 26 ] rectangle = 16 + 16 + 26 + 26 = 84-ft .
Perimeter of a 20-ft square = 4 x 20 = 80-ft .
The rectangle has the greater perimeter.
Wiki User
∙ 13y ago
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One pair of corresponding sides of two similar polygons measures 12 and 15 The perimeter of the smaller polygon is 30 Find the perimeter of the larger?
The perimeter of the larger polygon will have the same ratio to the perimeter of the smaller as the ratio of the corresponding sides. Therefore, the larger polygon will have a perimeter of 30(15/12) = 37.5, or 38 to the justified number of significant digits stated.
How do you calculate the top dimensions of a rectangle if you know its perimeter and bottom area?
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
If you double the side lengths of a rectangle why is the area of the new rectangle not twice as big as the original?
Look at it this way, suppose x is one side of the rectangle and y is the other. Then the area of the rectangle would be xy. Now if you double each side of the originial rectangle you would have each side as 2x and 2y. So the area of the new rectangle would be 2x*2y or 4xy. As you can see the new area is 4 times larger than the original.
Is it possible for a shape with a perimeter of of 3.00 to have a side length of 5 cm?
* no, that would mean would of your side lengh's is larger than your whole shape
Is an area or perimeter bigger?
Perimter is linear; area is two-dimensional. While the values may be either larger or smaller (for example, consider a square with one unit's width, then a square with 5 units' width), area will always be larger because of the extra dimension.
Which is larger the perimeter of a 2' 4' rectangle or the circumference of a circle with a diameter of 36?
The circumference of the circle is larger than the perimeter of the rectangle.
If a perimeter is 22 ft what is rectangle with an area larger than 30?
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Is The area of a rectangle always greater than the perimeter?
To answer this simply try a few out for yourself. In a 2x1 cm rectangle, the area is 2 cm squared and the perimeter is 6 cm In a 12x10 rectangle, the area is 120 cm squared and the perimeter is 44 cm. In some cases, the perimeter is larger and in others it is smaller. To answer your question, no, the perimeter of a rectangle is NOT always greater than its area.
Is the perimiter of 11 by 12 rectangle smaller or larger than the perimiter of a sqare with the same area?
11 x 12 rectangle has a larger perimeter = 46 units The 132 square unit area will give a square a perimeter of 45.9565 units
The perimeter of a rectangle is 18 cm and its dimensions are quadrupled What is the perimeter of the larger rectangle?
Length + Width = 9, becomes 36, eg 8 + 1 becomes 32 + 4 or 5 + 4 becomes 20 + 16 New perimeter is 2 x 36 = 72 cm
Rectangle whose perimeter is larger than area?
Perimeter is a unit of length. Area is a unit of area. The two units are not directly convertible.However, the area of a rectangle is length times width, and the perimeter is two times length plus two times width. Given constant perimeter, a square has maximum area, while a very thin rectangle has nearly zero area. (In calculus terms, the limit of the area as length or width goes to zero is zero.)Depending on how you want to name your units, you can always find a rectangle whose perimeter is "larger" than area, but this is a numerical trick that is not valid in any school of thought of mathematics that I know.
What is the perimeter of a rectangle if the area is 360 square centimeters?
Anything from almost 75,9 (if the rectangle were a square with each side 18,97 cm) to much larger, 722 if the rectangle is 1 cm by 360 cm or if the rectangle were 0,5 by 720 cm - still an area of 360 cm2! - the perimeter would be 1441cmGreater than 4 * sqrt 360
Is it sometimes always or never true that the perimeter of a rectangle is numerically greater than its area?
Sometimes. Experiment with a small square and with a large square (though any shape rectangle will do). A square of 4 x 4 has a perimeter of 16, and an area of 16. A smaller square has more perimeter than area. A larger square has more area than perimeter.
How is area perimeter and volume related?
In general the larger the perimeter (of a flat shape) the greater the area. Given two congruent shapes the one with the larger perimeter has a greater area.But two shapes that are not congruent (or almost so) do not follow this rule: for example a rectangle fifteen units long and one unit wide has an area of 15 square units and a perimeter of 32 units. While a square with edges four units has an area of sixteen square units (one more than the other rectangle) but a perimeter of only sixteen units (half that of the long thin rectangle).So too with surface area and volume. Of two congruent 3 dimensional shapes, the one with the larger volume will also have a larger surface area.
What do you do to the length and width of a rectangle if you want the perimeter to be the same as another rectangle but have a larger area?
YOu add a # to the width and then you subtract the same # from the length! If you want to go all the way and make the area as big as possible, then you want to make the length and width both 1/4 of the perimeter.
Can perimeter be larger than area?
yes if you have a 1 by 1 rectangle, you would have a perimeter of 4 but an area of 1 [ADDED} It's really a meaningless question because although such numbers suggest that, you cannot compare a linear dimension (perimeter) with an area.
Which rectangle has the greater perimeter 6 centimeters by 4 centimeters 6.5 centimeters by 2 centimeters?
6x4 has a perimeter of 2*(6+4) = 2*10 = 20 cm 6.5x2 has a perimeter of 2*(6.5+2) = 2*8.5 = 17 cm So the first has the larger perimeter.
