It factors to: (x-4)(x+1)
(x-1)(x-5)=x^2-6x +5 Because it is negative 5, I dont see an answer.
which of the following is a factor of x2 - 5x - 6
3x squared minus 25x minus 28
I'd substitute the values -2, 8 and 130 into the quadratic formula and wind up with two real solutions: 2 plus or minus -1 times the square root of 69 x = -6.306623862918075 x = 10.306623862918075
6(b - ac + b2 - bc)
2(5x + 7)(x - 5)
(m + 5)(3m - 1)
(x-1)(x-5)=x^2-6x +5 Because it is negative 5, I dont see an answer.
(x + 3)(x - 2)
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times". There is no trinomial in the question.
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-615 plus or minus 15 times the square root of 3281) divided by 2. x = 122.10010474859058 x = -737.10010474859058
To factor a trinomial in the form ax2 + bx + c, where a does not equal 1, the easiest process is called "factoring by grouping". To factor by grouping, you must change the trinomial into an equivalent tetranomial by rewriting the middle term (bx) as the sum of two terms. There is a specific way to do this, as demonstrated in the example.Take the quadratic trinomial 5x2 + 11x + 21. Find the product of a and c, or 5*2 = 10.2. Find factors of ac that when added together give you b, in this case 10 and 1.3. Rewrite the middle term as the sum of the two factors (5x2 + 10x + x + 2).4. Group terms with common factors and factor these groups.5x2 + x + 10x + 2x(5x + 1) + 2(5x + 1)5. Factor the binomial in the parentheses out of the whole polynomial, leaving you with the product of two binomials. 5x2 + 11x + 2 = (x + 2)(5x + 1)Notes:1. The same process is done if there are any minus signs in the trinomial, just be careful when factoring out a negative from a positive or vice versa.2. If you have a tetranomial on its own, you can skip the rewriting process and just factor the whole polynomial by grouping from the start.3. As in factoring any polynomial, always factor out the GCF first, then factor the remaining polynomial if necessary.4. Always look for patterns, like the difference of squares or square of a binomial, while factoring. It will save a lot of time.
9
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". x p cannot be a factor.
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (9 plus or minus 9i times the square root of 3) divided by 2y = 4.5 + 7.794228634059948iy = 4.5 - 7.794228634059948iwhere i is the square root of negative one.
Set up two brackets. Since 7 only has two factors, put 7x in one bracket and x in the other. The two other numbers will be a factor pair of 16 (16,1)(8,2)(4,4). Since the signs are minus, one of the brackets will be plus and one will be minus. Now you just have to put it together in a way that fits. We used to call that trial and error, now it's called guess and check. (7x + 4)(x - 4)
Without knowing the plus or minus values of the given terms then it can't be considered to be a quadratic expression.