That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (9 plus or minus 9i times the square root of 3) divided by 2
y = 4.5 + 7.794228634059948i
y = 4.5 - 7.794228634059948i
where i is the square root of negative one.
I assume the expression is y2+12y+27 as I cannot see the operation symbols between them (editor problem?). If you agree with this then y2 + 12y + 27 = y2 + 9y + 3y + 27 = y(y + 9) + 3(y + 9) = (y + 3)(y + 9)
It is: y2
9x^2-6xy+y^2 = (y-3x)^2 (y-3x)^2-81 -> ((y-3x)+9)((y-3x)-9)
4 - y2 can be written as 22 - y2. This has become of the form of x2 - y2.Expansion for x2 - y2 is (x+y)(x-y).So, 4 - y2 = 22 - y2 = (2+y)(2-y)
(y - 8)(y + 1)
9y-81=9*(y-9)
The GCF is 9y^2.
x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)
(3x - y)(3x - y) - 81
(y - z)(y - 5z)
There is a formula for the "difference of squares." In this case, the answer is (y + 9)(y - 9)
I assume the expression is y2+12y+27 as I cannot see the operation symbols between them (editor problem?). If you agree with this then y2 + 12y + 27 = y2 + 9y + 3y + 27 = y(y + 9) + 3(y + 9) = (y + 3)(y + 9)
(y - 7)(y - 2)
No. It's a trinomial.'tri' means 'three' termsThe three terms are [ y2 ], [ 2y ], and [ 1 ].
(y + 6)(y + 3)
y3 + 2y2 - 81y -162 = y2(y+2) - 81(y+2) =(y+2)(y2-81) = (y+2)(y-9)(y+9)
It is: y2