That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (9 plus or minus 9i times the square root of 3) divided by 2
y = 4.5 + 7.794228634059948i
y = 4.5 - 7.794228634059948i
where i is the square root of negative one.
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I assume the expression is y2+12y+27 as I cannot see the operation symbols between them (editor problem?). If you agree with this then y2 + 12y + 27 = y2 + 9y + 3y + 27 = y(y + 9) + 3(y + 9) = (y + 3)(y + 9)
It is: y2
9x^2-6xy+y^2 = (y-3x)^2 (y-3x)^2-81 -> ((y-3x)+9)((y-3x)-9)
4 - y2 can be written as 22 - y2. This has become of the form of x2 - y2.Expansion for x2 - y2 is (x+y)(x-y).So, 4 - y2 = 22 - y2 = (2+y)(2-y)
(y - 8)(y + 1)