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y=5 and x=-5
It works out that the solutions are: x = 3 and y = 2
There is no solution for those equations because the lines are parallel so, they never touch.
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
using the t-table determine 3 solutions to this equation: y equals 2x
Assuming x(2-10x)=21 to be solved for x, distribute to -10x2+2x=21, or 10x2-2x+21=0. By the quadratic equation, we can determine there are no real solutions because the square root of -836 does not exist. In imaginary solutions, we can reduce to 1/10*(1 + sqrt(-209)) and 1/10*(1-sqrt(-209)) as solutions.
Only one. 2x - 12x = 220 -10x = 220 x= 220/-10 x = -22
x=7
10
It works out that the solutions are: x = 3 and y = 2
The quadratic equation will have two solutions.
2x-3 = 9 2x = 9+3 2x = 12 x = 6
2x - 4 = -10 2x = -10 +4 2x = -6 x = -3
4 - 2x = 10 -2x = 10-4 -2x = 6 -x = 3 x = -3
2x+10=12 2x=2 x=1
2x - y = 8 x + y = 1 These are your two equations. They will have two solutions since you have two variables. The solutions are x=3 and y=-2
10
There is no solution for those equations because the lines are parallel so, they never touch.