Any pair of numbers where the 'y' is 5 more than the 'x'. There are an infinite number of suitable pairs. 2y-2x=10 2y-2x+2x=10+2x 2y=2x+10 divide both side by 2. y=x+5
(2, 1)
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
They are parallel lines.
2x+2y
(4, -1)
10-2y
parallel
(12, 1)
The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).
4x + 2y = 20 2y = -4x + 20 y = -2x + 10.......but you may also write it as y = 10 - 2x.
-2x=2y+5 +2x -2y -2y=2x+5 /-2 y=-1/1+2.5
4x+2y = 20 2y = -4x+20 y = -2x+10
y = -2x+10
X + ( 2Y - 2X - Y ) is equal to Y - X
Any pair of numbers where the 'y' is 5 more than the 'x'. There are an infinite number of suitable pairs. 2y-2x=10 2y-2x+2x=10+2x 2y=2x+10 divide both side by 2. y=x+5
The solution is:- x = 0 and y = 5