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Q: Which pair of numbers does the square root of 68 fall between?

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The square root of 103 is roughly 10.14889157, so it is between root 100 (10) and root 121 (11).

-5 and -4 or 4 and 5

Ordered pair (s)

sqrt(89) = -9.4 or +9.4 So one possible pair of consecutive integers between the square roots of 89 are 2 and 3.

Call the integer square roots of the specified pair of numbers l and g for lesser and greater respectively. Then, from the problem statement, g2 - l2 = 105. Possible values for l2 are successively 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, .... , and corresponding values for g2 are 106, 109, 114, 121, ... etc. The first of the latter series that is a perfect square number is 121. Therefore, the square numbers are 121 and 16.

Related questions

35.9999999999 and 36.0000000001

5 and 6

4 and 5 because the square root of 18 is about 4.242640687

17 and 19

53 and 55.

The square root of 103 is roughly 10.14889157, so it is between root 100 (10) and root 121 (11).

9 and 10 9 x9 =81 10 x 10 = 100

26 falls between 25 and 27.

58 falls between 57 and 59.

18 falls between 17 and 19.

The square root is between 5 and 6.

The answer is 2 and 3

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