Call the integer square roots of the specified pair of numbers l and g for lesser and greater respectively. Then, from the problem statement, g2 - l2 = 105. Possible values for l2 are successively 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, .... , and corresponding values for g2 are 106, 109, 114, 121, ... etc. The first of the latter series that is a perfect square number is 121. Therefore, the square numbers are 121 and 16.
They are; 8 and 9 but the square root of 68 is about 8.246211251
-5 and -4 or 4 and 5
The square root of 103 is roughly 10.14889157, so it is between root 100 (10) and root 121 (11).
An interval that remains the same throughout a sequence
This is easily solved by using two equations in 2 unknowns and solving the system. x + y = 111 x - y = 43 If have not yet had the pleasure of studying algebra and the answer is important to you, you could hope the numbers are positive integers and try all pair of numbers whose sum is 43: 1,42 2,41 3,40 and so on, until you find a pair whose difference is 43.
big cheese
16 -9
8464 and 3364
The answer to this question can not be answered , many apologies for the inconvenience.
1
They can be: 144-64 = 80
They are: 100-16 = 84
They are 25+49 = 74
2 and 3 is the only pair.
2 and 3 No other pair.
They are: 49+64 = 113
25 + 49 = 74