Put in this form. Y =mX + c
4Y - 2X = 0
4Y = 2X
Y = (1/2)X
============so,
X = 2
Y = 1
X = 4
Y = 2
X = - 2
Y = - 1
=============
(2, 1)....(4, 2)......(- 2, - 1)
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2x-4y = 16 -4y = -2x+16 y = 1/2x-4 Any equation that has a slope of 1/2 but a different intercept of -4.
Point Slope Form - Y=.5X+1.5
If: 2x-3y = -15 and x = 4y Then: x = -12 and y = -3
2x + 4y = 16 <=> 2x + 4y - 16 = 0 2x - 4y = 0 2x - 4y = 2x + 4y - 16 -8y = -16 y = 2 Substituting the known value for y in either of the original equations enables x to be determined. 2x + (4*2) = 16 : 2x = 16 - 8 : x2x = 8 : x = 4 2x - (4*2) = 0 : 2x - 8 = 0 : 2x = 8 : x = 4. The ordered pair satisfying both equations is (4,2)
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.