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If: 2x-3y = -15 and x = 4y
Then: x = -12 and y = -3
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∙ 11y ago
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What is the value of t when 5x equals -2 and 4y equals -4?
It is impossible to give the value of t when it is not defined.
What is the answer to 12-4y equals y-3?
12-4y=y-3 (subtract 12 from both sides) -4y=y-15 (subtract y from both sides) -5y=-15 (multiply both sides by -1 to make them positive) 5y=15 (divide by 5) y=3
What is 4y - 2 equals 6?
4y -2 = 6 4y = 6 + 2 4y = 8 y = 2
What are the solutions for the equations x equals 4y and 3x-2y equals 20?
x = 4y 3x - 2y = 20 Substituting the value of x into the second equation, 3*(4y) - 2y = 20 ie 12y - 2y = 20 or 10y = 20 so that y = 2 Then x = 4y = 4*2 = 8. So (x , y) = (8 , 2)
Could you find the possible value or values of y in the quadratic equation 4-4y-y2 equals 0?
-0.82 , -4.82
What is 4y-9 equals 15?
4y-9 = 15 4y = 15+9 4y = 24 y = 6
What is -4y-9 equals 15?
y = -6
What is 4y plus 12 equals?
That depends what the value of y is.
What is the value of t when 5x equals -2 and 4y equals -4?
It is impossible to give the value of t when it is not defined.
5x plus 4y equals 11 what is the value of y when x equals -1?
4
What do 4y-9 equals 15 equal too?
y = 6
How do you solve this equation 4y plus 228 equals 352?
For 4y+228 = 352 the value of y works out as 31.
What is x equals 4y-2 and x equals 6y plus 8?
By definition: 4y-2 = 6y+8 4y-6y = 8+2 -2y = 10 y = -5 and by substituting this value into the equation x = -22
How do you solve the system of equation 5x-4y equals 14 an 7x-4y equals 26d?
7x-4y = 26 5x-4y = 14 Subtract the bottom equation from the top squation remembering that a minus minus is equal to a plus therefore - 4y - - 4y = 0 2x = 12 Divide both sides by 2 to find the value of x: x = 6 Substitute the value of x into the original equations to find the value of y: Therefore: x = 6 and y = 4
5x - y equals 27 5x plus 4y equals 42?
27 + y = 42 - 4y so 5y = 15 making y = 3 and x = 6
5x - 4y equals 14 7x - 4y equals 26?
First rearrange these simultaneous equations in the form of: 7x-4y = 26 5x-4y = 14 Subtract the bottom equation from the top equation remembering that a - - is equal to a plus. So, -4y - - 4y = 0 2x = 12 and therefore it follows that x = 6 Substitute the value of x into the original equations to find the value of y: Therefore: x = 6 and y = 4
X plus 4y equals 1 2x-2y equals -8?
x+4y = 1 2x-2y = -8 Mutiply all terms in the bottom equation by 2 and then add them both together: 5x = -15 x = -3 Substitute the value of x into the equations to find the value of y: So: x = -3 and y = 1
