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When the parabola concave downward and upward?
If the number in front of the x squared is negative, then the parabola will open upwards. The opposite occurs when the number is positive.
What does changing the value of a from a negative number to a positive number cause the parabola to do?
open upward
The equation below describes a parabola. If a is negative which way does the parabola open y ax2?
Down
What way does a parabola open if a is negative?
Downwards
How do you graph quadratic functions in vertex form?
The standard form of quadratic function is: f(x) = a(x - h)^2 + k, a is different than 0 The graph of f is a parabola whose vertex it is the point (h, k). If a > 0, the parabola opens upward; if a < 0, the parabola opens downward. Furthermore, if |a| is small, the parabola opens more flatly than if |a| is large. It is a general procedure for graphing parabolas whose equations are in standard form: Example 1: Graph the the quadratic function f(x) = -2(x - 3)^2 + 8 Solution: Standard form: f(x) = a(x - h)^2 + k Given function: f(x) = -2(x - 3) + 8 From the give function we have: a= -2; h= 3; k = 8 Step 1. Determine how the parabola opens. Note that a = -2. Since a < 0, the parabola is open downward. Step 2. Find the vertex. The vertex of parabola is at (h, k). because h = 3 and k = 8, the parabola has its vertex at (3, 8). Step 3. Find the x-intercepts by solving f(x) = 0. Replace f(x) with 0 at f(x) = -2(x - 3)^2 + 8 and solve for x 0 = -2(x - 3)^2 + 8 2(x - 3)^2 = 8 (x- 3)^2 = 4 x - 3 = square radical 4 x - 3 = 2 or x -3 = -2 x = 5 or x = 1 The x- intercepts are 1 and 5. Thus the parabola passes through the points (1, 0) and (5, 0), this means that parabola intercepts the x-axis at 1 and 5. Step 4. Find the y-intercept by computing f(0). Replace x with 0 in f(x) = _2(x - 3)^2 + 8 f(0) = -2(0 - 3)^2 + 8 f(0) = -2(9) + 8 f(0) = -10 The y-intercept is -10. Thus the parabola passes through the point (0, -10), this means that parabola intercepts the y-axis at -10. Step 5. Graph the parabola. With a vertex at (3, 8), x-intercepts at 1 and 5, and a y-intercept at -10. The axis of symmetry is the vertical line whose equation is x = 3. Example 2: Graphing a quadratic function in the form f(x) = ax^2 + bx + c Graph the quadratic function f(x) = -x^2 - 2x + 1 Solution: Here a = -1, b = -2, and c = 1 Step 1. Determine how the parabola opens. Since a = 1, a < 0, the parabola opens downward. Step 2. Find the vertex. We know that x-coordinate of the vertex is x = -b/2a. Substitute a with -1 and b with -2 into the equation for the x-coordinate: x = - b/2a x= -(-2)/(2)(-1) x = -1, so the x-coordinate of the vertex is -1, and the y-coordinate of the vertex will be f(-1). thus the vertex is at ( -1, f(-1) ) f(x) = -x^2 - 2x +1 f(-1) = -(-1)^2 - 2(-1) + 1 f(-1) = -1 + 2 + 1 f(-1) = 2 So the vertex of the parabola is (-1, 2) Step 3. Find the x-intercepts by solving f(x) = o f(x) = -x^2 -2x + 1 0 = -x^2- 2x + 1 We can't solve this equation by factoring, so we use the quadratic formula to solve it. we get to solution: One solution is x = -2.4 and the other solution is 0.4 (approximately). Thus the x-intercepts are approximately -2.4 and 0.4. The parabola passes through ( -2.4, 0) and (0.4, 0) Step 4. Find the y-intercept by computing f(0). f(x) = -x^2 - 2x + 1 f(0) = -(0)^2 - 2(0) + 1 f(0) = 1 The y-intercept is 1. The parabola passes through (0, 1). Step 5. graph the parabola with vertex at (-1, 2), x-intercepts approximately at -2.4 and 0.4, and y -intercept at 1. The line of symmetry is the vertical line with equation x= -1.
Which way does a parabola open when the coefficient of its y2term a is negative?
Nose points right, opens to the left.
if the parabola open upward a is?
positive.
If a is positive which way does the parabola open?
Upwards like a letter U
Does the parabola open up or down?
It does both depending if it is positive or negative
Which way does a parabola open when the coefficient of its y term a is negative?
When the coefficient of the y term ( a ) in the equation of a parabola is negative, the parabola opens downward. This means that its vertex is the highest point on the graph. Conversely, if ( a ) were positive, the parabola would open upward.
What The equation y ax2 describes a parabola. If the value of a is positive which way does the parabola open?
If the value of ( a ) in the equation ( y = ax^2 ) is positive, the parabola opens upwards. This means that the vertex of the parabola is the lowest point, and as you move away from the vertex in either direction along the x-axis, the value of ( y ) increases. Conversely, if ( a ) were negative, the parabola would open downwards.
Given the standard equation for a parabola opening left or right which way does a parabola open when the coefficient of the y2-term a is positive?
right
If a is positive which way does a parabola open?
If ( a ) is positive in the quadratic equation ( y = ax^2 + bx + c ), the parabola opens upward. This means that the vertex of the parabola is the lowest point on the graph, and as you move away from the vertex in either direction along the x-axis, the values of ( y ) increase. Conversely, if ( a ) were negative, the parabola would open downward.
When the parabola concave downward and upward?
If the number in front of the x squared is negative, then the parabola will open upwards. The opposite occurs when the number is positive.
Which way does a parabola open when the coefficient of its x2 term a is positive?
It is like the letter U.
What does changing the value of a from a negative number to a positive number cause the parabola to do?
open upward
Given the standard equation for a parabola opening left or right which way does a parabola open when the coefficient of the y2-term a is positive Left or right?
left
