0
Any variable multiplied by zero equals zero, so you can multiply both sides of the equation by zero, but you just destroy any form of a solution you may have. For example:
x = 5
x*0 = 5*0
0 = 0
Yup!
By the way, what is x?
Algebra is basically finding a missing variable or finding a relationship between many variables.
Multiplying by 0 removes information that is crucial to solving for variables.
Wiki User
∙ 13y ago
Wiki User
∙ 14y agoUnless my math skills are failing me, you can.
Multiplying both sides of an equation by zero should make both sides equal to zero and it's a true statement to say 0 = 0.
For example, 3x + 2 = 5.
If you multiply both sides by zero, you'd get 0(3x + 2) = 0 * 5
Which comes out to 0 = 0.
This doesn't exactly help you solve the problem though, because you're eliminating the variable x.
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How do you multiply exponents when the bases are not the same?
u cant they have to be the same (:
Why cant the zero product property be used to solve every quadratic equation?
If the discriminant of a quadratic equation is less than zero then it will not have any real roots.
How do you solve a linear equation?
A linear equation simply means there are no squared's or cubed's or any other nasty bits in it. It could look like this:15x + 19 = 49To solve this, you subtract 19 from both sides to give:15x = 30Then divide both sides by 15 so you find x = 2You can sometimes find an equation with two variables in it such as 4x + 5y = 100. However you cant find two variables form one equation, you need two and this is called simultaneous equations.On the secondary problem, such as 4x + 5y = 100, you can use the substitution method.It involves setting the x to zero and solving, and then setting y to zero and solving.Let's solve for "y":4(0) + 5y = 1005y = 1005y/5 = 100/5y = 20Therefore the ordered pair is (0, 20)Let's solve for "x":4x + 5(0) = 1004x = 1004x/4 = 100/4x = 25Therefore the ordered pair is: (25, 0)
How do you solve equations approximately?
You have to isolate your variable to one side of the equation. Add, subtract, multiply, and divide when necessary. Sometimes you will get an approximate answer. This means you cant show all of the decimals. For exmaple lets say your variables equals 1/3. Well you cant possibly write 3 infinite because 1/3=0.333 (with infinite 3s). So you write approximately equal to 0.333 Also when you have a variable that is equal to pi (3.14159... etc) you cant possibly write the infinite amount of decimals for this so you write 3 or 4 decimals and then make sure you indicate it is approximate and not equal.
The width of a rectangle is 6 inches less than twice its length Find the dimension of the rectangle if its area is 108 square inches?
Imagine a rectangle, the width is called 'Y' and the length is 'X'. the area is X * Y (because the area of a rectangle is the width and the length multiplied) we know the area is 108 so: XY = 108 http://wiki.answers.com/Q/The_width_of_a_rectangle_is_6_inches_less_than_twice_its_length_Find_the_dimension_of_the_rectangle_if_its_area_is_108_square_inches so basically : Y = 2X - 6 now do simultaneuos equations Y = 2X - 6 XY = 108 you can substitute Y from the first equation into the second one so X(2X - 6) = 108 (now multiply out the brackets by timesing everything inside the brackets (2X - 6) by everything out side the brackets (X)...) i cant do 2xsquared for some reason 2XX - 6X = 108 (simplofy by dividing the equation by two as it is divisble by two) XX - 3X = 54 move 54 to the other side by taking 54 away from both sides XX - 3X - 54 = 0 factorise (X - 9)(X + 6) = 0 now either X - 9 = 0 or X + 6 = 0 because to get the product of 0 you must mutiply it by 0 try both out X - 9 = 0 OR X + 6 = 0 add 9 to both sides subtract 6 from both sides X = 9 X = -6 so X is either 9 or -6 ---- but as we are talking about lengths, X has to be 9 because lengths can not be negative so X = 9 the equation from the begining Y = 2X - 6 will help as we now know X substitute X Y = 2(9) - 6= 18 - 6= 12 X (the length) = 9 Y (the width) = 12 wahey! you know the dimensions!Let the width be (2x+6) and the length be x:width*length = area(2x-6)*x = 108 sq inches2x2-6x-108 = 0Solving the above quadratic equation works out as:x = -6 or x = 9 it must be the latter because dimensions can't be negative.Therefore: width = 12 inches and length = 9 inchesCheck: 12*9 = 108 square inches
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Well it fully depends on what type of copper you have. if you have Cu1+ then when you do an ionic equation and switch the ion charges, then the compound you would get would be Cu2O. If you had Cu2+ then the compound would end up being CuO. You cant just put two things together and assume its right. You have to do an ionic equation and then balance your reaction.
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you cant
Why cant you multiply with just a whole number?
You can, in the right circumstances.
How do you multiply exponents when the bases are not the same?
u cant they have to be the same (:
