Shapes with the same area can be different sizes. If you restrict yourself to integers, a rectangle with an area of 12 square inches can have the following dimensions:
1 x 12 (perimeter 26)
2 x 6 (perimeter 16)
3 x 4 (perimeter 14)
The long skinny piece has most of its area near the edges. The one that's most like a square has most of its area in the center.
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No, in general that is not true. For two similar figures it is true. But you can easily design two different figures that have the same perimeters and different areas, or the same area and different perimeters. For example, two rectangles with a different length-to-width ratio.
If the sides are in cm, then you would multiply the length of the shape by the width, which equals area. And area is in the unit of the sides but squared. So in this example it would be cm2. ========================================= The answer to the question is: You can't. The perimeter doesn't tell you what the area is. You can have two different drawings with the same perimeter and different areas, or with the same area and different perimeters. Even if they're both triangles, or both rectangles, etc. You can't take perimeter and 'work out' area from it.
No.It is not possible for the shape with the same perimeter to have the same area. This is because, to do this, you would have to cut up two shapes into eight pieces, add the amount of them all together and divide them by 7.559832076. By doing this you are breaking the seventh note, this is against the laws of trigonometry there by breaking this rule of concentration, so this statment; having shapes with the same perimeter have the same area, is therefor not true!Thank you.
Similar shapes.
You can't tell. The perimeter doesn't tell you the area. There are an infinite number of rectangles that all have the same perimeter but different areas. Here are a few that all have perimeters of 28 cm: 1 x 13 . . . . . Area = 13 2 x 12 . . . . . Area = 24 3 x 11 . . . . . Area = 33 4 x 10 . . . . . Area = 40 5 x 9 . . . . . Area = 45 6 x 8 . . . . . Area = 48 7 x 7 . . . . . Area = 49