my idea is that to find the area of a 2 dimensional figure you have to multiply length *width which equal the area except a triangle and some other figure
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
Area = length x width
the area of a rectangle = length x widthwe can rearrange this to give uslength of a rectangle = area/ width
Area=Length X Width
The perimeter is equal to length + length + width + width while area is length x width. Both measurements are found by using width and length.
Area is l (length) x w (width), Volume is measured with l (length) x w (width) x h (height).
Area = length x width Length = area/width
36, area is equal to length X width, perimeter is equal to 2(length)+2(width) in a square length is equal to width, so we take the square root of the area to find that both are 9, which means the perimeter is 9 X 4, 36.
The area of a rectangle is equal to its length times it width. A = l x w
the area is equal to the width X the length or, in this case, 15.
Perimeter: Add the length of the four sides. Area: Multiply length x width.
my idea is that to find the area of a 2 dimensional figure you have to multiply length *width which equal the area except a triangle and some other figure
It not possible you nit witt that is not true length x width = area If you know length and area, solve width width = area / length then 2 x length + 2 x width = perimeter
divide surface area by width Sorry It is a little more complicated than that. Surface area = (2 X length X width) + (2 X length X height) + (2 X width X height) Solve for height Surface area - (2 X length X width) = 2height(length + width) (Surface area - (2 X length X width))/2(length + width) = height
area of a rectangle = length x width
The area of a rectangle is length x width. Since in the case of a square, both are equal, you simply multiply length x length.