Since no integer multiplied by itself can yield 111, it is not a perfect square. 121, however, is a perfect square. Its square root is 11.
96 + 4 = 100 96 + 25 = 121 96 + 100 = 196 96 + 529 = 625
121, 144, 169, 196
The square roots of 121 are 11 and -11.
Call the integer square roots of the specified pair of numbers l and g for lesser and greater respectively. Then, from the problem statement, g2 - l2 = 105. Possible values for l2 are successively 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, .... , and corresponding values for g2 are 106, 109, 114, 121, ... etc. The first of the latter series that is a perfect square number is 121. Therefore, the square numbers are 121 and 16.
121 is, itself, a perfect square.
121
Yes. 121 = 11 x 11.
No.... Number nearest to 124 which i a perfect square is 121 & then 144
100
121.
Since no integer multiplied by itself can yield 111, it is not a perfect square. 121, however, is a perfect square. Its square root is 11.
No, it is not. For it to be a perfect square, the square root of it would have to be an integer, but √120 ≈ 10.954. 100 and 121 are perfect squares nearest to 120. ■
100
The smallest perfect square is 121.
11 squared is 121
1, 11, and 121. (This number has an odd number of factors because it is a perfect square: 11 * 11 = 121.)