its not...
5x2 - 136 = 44 5x2 - 136 + 136 = 44 + 136 5x2 = 180 5x2/5 = 180/5 x2 = 36 √x2 = √36 x = ±6
(5x-6)(x-3)
= 5x2+70-16+9x-2 = 5x2+9x+52 = 5x2+9x1+52 This implies coefficient of degree 1 is 9. Ans.
(5x + 13)(x - 3) so x = either -13/5 (ie -2.6) or 3.
To factor any term, divide by the LCF (largest common factor) of the term. For 5x2-45, the LCF is 5. 5x2-45 = 5(x2-9) It can, of course, be factored even further to become: 5(x2-9) = 45(x2/9 - 1) but when factoring, we usually don't need to go past 5(x2-9) (for example, you've figured out that x2 = 9, thus x = +/- 3.)
(5x - 1)(x + 3)5x2 + 14x - 3= 5x2 + 15x - x - 3= 5x(x + 3) - 1(x + 3)= (5x - 1)(x + 3)
5x2 = 3 then x2 = 3/5 so that x = sqrt(3/5) = ± 0.7746
5x2-18x+9 = (5x-3)(x-3)
5x2 + 3x - 1 does not have rational factors.
(5x - 3)(x - 3)
5x2 + 2x - 3 = 0 5x2 + 5x - 3x - 3 = 0 5x(x + 1) - 3(x + 1) = 0 (5x - 3)(x + 1) = 0 So 5x - 3 = 0 or x + 1 = 0 ie x = 3/5 or x = -1
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
5x2+14x-3 -15. 15*-15x2-x+15x-3[5xx x] [3*5x 3]x(5x-1)+3(5x-3)Answer: (5x-1)(x+3)
3
5x(x+3)
5x2=10
(5x - 1)(x + 3)