log x2 = 2 is the same as 2 log x = 2 (from the properties of logarithms), and this is true for x = 10, because
log x2 = 2
2 log x = 2
log x = 1
log10 x = 1
x = 101
x = 10
(check)
All real numbers that are greater than or equal to zero
It can not be factored because its discriminant is less than zero
If you mean: (x+3) squared = (x+2) squared +11 Then the value of x works out as 3
Six less than a number w squared is written algebraically as w2 - 6
You don't. There's no question there, and nothing that needs solving. "16 less than x squared" is written as (x2 - 16)
The number than when squared equals 110 is the square root of 110 = ±10.488 (3dp)
Since 0.50 squared equals 0.25, 0.50 squared is less than 0.50.
The greatness of 4 squared and 3 squared is expressed by the equation: 16 - 9 which equals 7.3 squared equals 3 x 3 = 94 squared equals 4 x 4 = 1616 - 9 = 7
To find out how much greater 8 squared (64) is than 7 squared (49), you simply subtract 49 from 64, which equals 15. Therefore, 8 squared is 15 greater than 7 squared.
a number equals 2
Your Problem: X - 4 = ?Current Problem: 3 [squared] - 4 = ?How: When a numbered is squared, it means you multiply it against itself. So, 3 squared equals 3x3.3x3 = 9So, you would then take 9 and minus it by 4, which would than equal 5.Answer:3 [squared] - 4 = 5or9 - 4 = 5
To find the length of AC, use the Pythagorean theorem. AC equals the square root of (AB squared + BC squared), which is the square root of (9 squared + 12 squared), giving AC = square root of (81 + 144) = square root of 225 = 15 centimeters.
All real numbers that are greater than or equal to zero
y is greater than 0 x exist in a set of real numbers
It can not be factored because its discriminant is less than zero
There are no real solutions. The discriminant (b squared -4ac) is less than 0, so there are 2 imaginary solutions and 0 real ones.
It has no solutions because the discriminant is less than zero.