No.
It would not because 8^2 + 9^2 = 10^2 is not true. (Pythagorean Theorem.)
64 + 81 = 100
With 3, 4, and 5, however, a right triangle is formed:
3^2 + 4^2 = 5^2
9 + 16 = 25
25 = 25
!
it is an acute triangle.
false In order for this to be a right triangle, the sum of the squares of the two shorter sides would have to equal the square of the longest side. 102=100 242= 576 272=729 102+242= 676, which does not equal 272=729, so a triangle with these lengths is not a right triangle.
Yes.
10
10(radical "2") units, or about 14.1 units.
Yes the given dimensions would form a right angle triangle.
The given dimensions would not form a right angle triangle but in general the are of a triangle is 0.5*base*perpendicular height
No.
No because the given dimensions would not form a triangle.
If these lengths did form a right triangle then Pythagorean theorem would be satisfied a^2+b^2 = c^2 since 10 is the largest number it must be the hypotenuse (c) left side=9^2+3.6^2, right side= 10^2 LS= 93.96, RS= 100, LS does NOT equal RS Therefore these three lengths cannot combine to form a triangle.
Yes the dimensions given would make a right angle triangle
If you mean units of 6 8 and 10 then yes they can form the sides of a right angle triangle.
I would hazard a guess and say it was 10.
It could have an area of 10 sq cm.
To determine if the lengths 75, 10, and 95 can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 95. Checking the equation: (75^2 + 10^2 = 5625 + 100 = 5725) and (95^2 = 9025). Since (5725 \neq 9025), the lengths 75, 10, and 95 do not form a right triangle.
No because it does not comply with Pythagoras; theorem if the lengths were 10, 24 and 26 then it would be.
it is an acute triangle.