If these lengths did form a right triangle then Pythagorean theorem would be satisfied
a^2+b^2 = c^2
since 10 is the largest number it must be the hypotenuse (c)
left side=9^2+3.6^2, right side= 10^2
LS= 93.96, RS= 100, LS does NOT equal RS
Therefore these three lengths cannot combine to form a triangle.
No.
316 = (3 x 100) + (1 x 10) + (6 x 1)
A triangle has 3 sides.
This is a scalene triangle as it has no equal sides or angles. It is not a right angle triangle.
If the length of only one side is known, it is not possible to determine whether or not the triangle is right angled.
No.
316 in expanded form is 300 + 10 + 6.
Yes the given dimensions would form a right angle triangle.
If you mean units of 6 8 and 10 then yes they can form the sides of a right angle triangle.
The given dimensions would not form a right angle triangle but in general the are of a triangle is 0.5*base*perpendicular height
316 = (3 x 100) + (1 x 10) + (6 x 1)
Expanded form means to separate each number out to its place in a place value chart or table. So with 12, the 1 is in the _____ place and the 2 is in the _____ place. So with 12, it's really 10 + 2.With 316, the 3 is in the ______ place, the 1 is in the _____ place, and the 6 is in the _____ place. So 316 would be _____ + ______ + ______.
it is an acute triangle.
No. For example, say the two angles are 10° and 20°. Then the other angle is 180°-10°-20°=150° and that is not a right angle. But if the triangle has two equal acute angles of 45 degrees then the 3rd angle must be 90 degrees which will form a right angle triangle.
10^2 + 12^2 is not equal to 16^2, so it is not a right triangle.
The hypotenuse of a right triangle with legs of 8 and 10 is: 12.81
A triangle has 3 sides.