6x - 5y = 15 6x - 6x - 5y = 15 - 6x -5y = -6x + 15 (-5y)/-5 = (-6x)/-5 + 15/-5 y = 6/5x - 3 where 6/5 is the slope and y-intercept is -3.
If we write the problem as 6x-5=x2, then we can write in the form of ax2+bx+c: -x2+6x-5. Then we can use the quadratic equation, x = (-b ± √(b2 - 4ac))/2a, and put in our own values to get the equation x = 3 ± 2. Therefore, x1= 1 and x2=5.
log (6x + 5) = 26x + 5 > 06x + 5 - 5 > 0 - 56x > - 56x/6 > -5/6x > -5/6log (6x + 5) = 210^2 = 6x + 5100 = 6x + 5100 - 5 = 6x + 5 - 595 = 6x95/6 = 6x/695/6 = xCheck:
(6x + 5)(6x - 5)
5
y=(6x-5)/3
5
6x - 5y = 15 6x - 6x - 5y = 15 - 6x -5y = -6x + 15 (-5y)/-5 = (-6x)/-5 + 15/-5 y = 6/5x - 3 where 6/5 is the slope and y-intercept is -3.
lets say you have to write 5x+6y=-12 in function form. when you are writing an equation in function form, you usually solve for f(x) or g(x), but in this case, y is the same as f(x) or g(x). so to write 5x+6y=-12 in function form, you do this: 5x+6y=-12 6y= -5x -12 subtract 5x from both sides y= -5/6x -2 divide both sides by 6
If we write the problem as 6x-5=x2, then we can write in the form of ax2+bx+c: -x2+6x-5. Then we can use the quadratic equation, x = (-b ± √(b2 - 4ac))/2a, and put in our own values to get the equation x = 3 ± 2. Therefore, x1= 1 and x2=5.
That depends on what you mean by "6x 5", which could be 6x * 5, 6x + 5, 6x - 5, 6x / 5, 6x5, etc.
6x - 5 -5 = 0 6x -10 = 0 +10=+10 6x=10 x= about 1.4
x = -3y = -14
6x5(x2 - 6x + 3)
As a polynomial in standard form, x plus 5x plus 2 is 6x + 2.
6x-5 = 7, 6x = 7+5, 6x = 12, x = 2
5-6x=5 -6x=0 X=undefined There is no answer its a trick question