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6x - 5
6x = 5
x = 5/6
f(x)=5/6 which is a constant function.
But if it was
y=6x-5, then
it would be
f(x)=6x-5
6x - 5y = 15 6x - 6x - 5y = 15 - 6x -5y = -6x + 15 (-5y)/-5 = (-6x)/-5 + 15/-5 y = 6/5x - 3 where 6/5 is the slope and y-intercept is -3.
If we write the problem as 6x-5=x2, then we can write in the form of ax2+bx+c: -x2+6x-5. Then we can use the quadratic equation, x = (-b ± √(b2 - 4ac))/2a, and put in our own values to get the equation x = 3 ± 2. Therefore, x1= 1 and x2=5.
log (6x + 5) = 26x + 5 > 06x + 5 - 5 > 0 - 56x > - 56x/6 > -5/6x > -5/6log (6x + 5) = 210^2 = 6x + 5100 = 6x + 5100 - 5 = 6x + 5 - 595 = 6x95/6 = 6x/695/6 = xCheck:
(6x + 5)(6x - 5)
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