i have a couple 67+3 59+11 53+17 47+23 41+29
how many ways can you get a sum of 1?
1 + 17 = 18 5 + 13 = 18 7 + 11 = 18
16 = 1+15, 3+13, 5+11, 7+92,3,5,7,11,13 are primes < 1616 = 3+13 or 5+11
sum = 2n + 3m
m + 8
100 = 62 + 82 = 82 + 62 and there is no other way
100 can be expressed as the sum of two primes in 6 different ways (ignoring order): 100 = 3+97 = 11+89 = 17+83 = 29+71 = 41+59 = 47+53
3 + 97 11 + 89 17 + 83 29 + 71 41 + 59 47 + 53 I think these are all of them.
Two, if the order of the primes is ignored.
12=5+7
How about: 17+7 = 24, 19+5 = 24 and 11+13 = 24 as three examples
There are not three odd primes with the sum of 14. The sum of three odd primes will be an odd number.
There are infinitely many ways.
All prime numbers greater than 2 are odd numbers. For an odd prime to be written as the sum of two primes, one of the primes must be 2 because two odd primes will produce an even sum. 11 cannot be written as the sum of two primes. 13 = 2 + 11. 17 cannot be written as the sum of two primes. 19 = 2 + 17.
Not true. 2 + 3 = 5, where all three are primes. One of the primes in the sum must be 2, otherwise both primes would be odd and their sum would be even (and >2) and therefore not prime. Such primes: p and p+2 [3 and 5 in the above example] are known as twin primes and there are infiitely many twin primes.
It is not. Of the infinitely many primes only one (the number 2) is even, the rest are all odd. The sum of any two primes other than 2 is even and therefore not a prime. If one of the primes in the sum is 2 then the sum is a prime only if the other is the lower of a pair of twin primes. So, while it is possible, it is certainly more likely that the sum is a composite.
Three of them.