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I assume your trying to solve for the x variable? Use the quadratic formula (Google it) to find the roots to a second order equation (equation that contains a variable to power of 2). Using that equation, you get x values of 6 and -3. The only other way to solve it is with trial and error, which can be quite tedious.
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X2 plus 3x - 18 equals 0?
x^2+3x-18=0 (x+6)(x-3)=0
One of the roots of the equation x2 plus 3x - 18 equals 0 is 3 what is the other root?
x2 + 3x - 18 = 0 (x - 3)(x + 6) = 0 x = 3 or -6
What binomial is a factor of x2 plus 3x - 18?
The factors are (x + 6) and (x - 3)
What is the correct classification of x2 3x 8?
The expression x2 + 3x +8 is a quadratic trinomial.
Divide x2-3x-10 by x-5?
x2 - 3X - 10 = (X - 5)(X + 2)So, (X2 - 3X -10) / (X-5) = X + 2
What is a factor of x2 plus 3x-18?
x2 + 3x - 18 = x2 + 6x - 3x - 18 = x(x + 6) - 3(x + 6) = (x + 6)(x - 3)
Answer of Factor the polynomial x2 3x-18?
x2 + 3x - 18 = (x + 6)(x - 3)
How do you factor xsquared-3x-18?
We have, f(x) = x2-3x-18 f(x) = x2-3x-18 = x2-6x+3x-18 = x(x-6)+3(x-6) = (x+3)(x-6) Factors are (x-6) and (x+3).
What is the answer for x2 plus 3x-18 equals 0?
X2 + 3X - 18 = 0What two factors of - 18 add up to 3 ??(X - 3)(X + 6)============so, by the zero sum rule,X = 3X = - 6
If 3x-1 equals 11 what is the value of x2 plus 2?
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
What is x2-3x-18 factorised?
(x-6)(x+3)
X2 plus 3x - 18 equals 0?
x^2+3x-18=0 (x+6)(x-3)=0
One of the roots of the equation x2 plus 3x - 18 equals 0 is 3 what is the other root?
x2 + 3x - 18 = 0 (x - 3)(x + 6) = 0 x = 3 or -6
How do you factor x2-3x-28?
x2-3x-28
Can you complete the square factor and use the quadratic formula to solve these two equations x2-4x-21 equals 0 and x2-3x-18 equals 0?
x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6
If 3X - 1 equals 11 what is the value of X2 plus X?
3x-1 = 11 3x = 11+1 = 12 x = 12/3 = 4 Therefore: x2 + 2 = 16 + 2 = 18
Factor x4 - 3x3 - 7x2 plus 27x -18?
First, it is important to regroup, so I am going to rearrange this equation: (x4 - 7x2 - 18 - 3x3 + 27x I can now factor the first three terms and the last two terms: (x4 - 7x2 - 18) becomes (x2 - 9)(x2 + 2) -3x3 + 27x becomes -3x(x2 - 9); so the new equation looks like: (x2 - 9)(x2 + 2) - 3x(x2 - 9) From here, factor out what is common, in this case- x2- 9. Therefore, you will have (x2 - 9)(x2 + 2 - 3x), which can be rearranged to (x2 -9)(x2 - 3x + 2). Further factoring reveals (x + 3)(x - 3)(x - 1)(x - 2) as the final answer.
