x2-4x-21 = 0 => x = -3 or x = 7
x2-3x-18 = 0 => x = -3 or x = 6
x^2 -8x-4=0 x=[8±√(64+16)]/2 x=(8±4√5)/2 x=4±2√5
Two equations: a linear one in y and a quadratic in x.
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
x^2 -8x-4=0 x=[8±√(64+16)]/2 x=(8±4√5)/2 x=4±2√5
Two equations: a linear one in y and a quadratic in x.
It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
Yes
(x - 3)(x + 1)
X= 1.567764363, -9.567764363
The first step is to show an example of the quadratic equation in question because the formula given is only the general form of a quadratic equation.