x2-4x-21 = 0 => x = -3 or x = 7
x2-3x-18 = 0 => x = -3 or x = 6
x^2 -8x-4=0 x=[8±√(64+16)]/2 x=(8±4√5)/2 x=4±2√5
Two equations: a linear one in y and a quadratic in x.
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
x^2 -8x-4=0 x=[8±√(64+16)]/2 x=(8±4√5)/2 x=4±2√5
Two equations: a linear one in y and a quadratic in x.
It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.
If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3
How about finding the solutions of the quadratic equation: x^2-14x+49 = 0
Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
x is equals to 0 or 1. How is it solved? .... x.x =x x.x - x = 0 which can be solved by the usual formula for quadratic equations, or.. x.(x-1)=0 x= 0 or x-1 =0 x=0 or x=1
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
(x - 3)(x + 1)