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Q: Can you complete the square factor and use the quadratic formula to solve these two equations x2-4x-21 equals 0 and x2-3x-18 equals 0?

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x^2 -8x-4=0 x=[8±√(64+16)]/2 x=(8±4√5)/2 x=4±2√5

Two equations: a linear one in y and a quadratic in x.

If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3

Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.

X= 1.567764363, -9.567764363

Related questions

The Quadratic Formula song: (my grade saver) To the tune of the jack in the box song X equals negative B plus or minus square root of B squared minus 4AC all over 2A :)

It is a quadratic equation and its solutions can be found by using the quadratic equation formula.

x^2 -8x-4=0 x=[8±√(64+16)]/2 x=(8±4√5)/2 x=4±2√5

Two equations: a linear one in y and a quadratic in x.

It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.

If: x2+x = 12 Then: x2+x-12 = 0 And using the quadratic formula: x = -4 or x = 3

How about finding the solutions of the quadratic equation: x^2-14x+49 = 0

Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.

(x - 3)(x + 1)

X= 1.567764363, -9.567764363

Yes

Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523

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