No because the discriminant of the given quadratic expression is less than zero.
3x2+14x+8 = 0 x = -2/3 or x = -4
If: x^2 +18x = 29 Then completing the square: (x+9)^2 -81 = 29 or (x+9)^2 = 110
x=b-a
I assume you mean the equation 2x2 + 12x - 10 = 0. Divide by 2: x2 + 6x - 5 = 0 To complete the square, the constant part (the part with no variable) must be half the linear part (1/2 of 6), squared, so in this case you add 14 to each side: x2 + 6x +9 = 14 This can be factored: (x+3)2 = 14 Now, just take the square root of each side: x + 3 = (plus-or-minus) 14 Solve the resulting two equations (one for plus, one for minus).
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This quadratic equation has no solutions because the discriminant is less than zero.
It cannot be solved because the discriminant of the quadratic equation is less than zero
68
No because the discriminant of the given quadratic expression is less than zero.
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
How do you solve 4y plus x equals 8
2x2+12x+1 = 0 By dividing all terms in the quadratic equation by 2 will make completing the square easier to work out: x2+6x+0.5 = 0 (x+3)2+0.5 = 0 (x+3)2-9+0.5 = 0 (x+3)2-8.5 = 0 (x+3)2 = 8.5 x+3 = the square root of 8.5 x = -3 and plus or minus the square root of 8.5
x2 - 16x + 68 = 5 (x - 8)2 + 4 = 5 (x - 8)2 = 1 x - 8 = 1 or -1 x = 9 or 7
This quadratic equation which will have two solutions can be solved by completing the square or by using the quadratic equation formula.Completing the square:x2+18x+4 = 0(x+9)2+4 = 0(x+9)2+4-81 = 0(x+9)2 = 77x+9 = + or - the square root of 77x = -9 + or - the square root of 77If you're not too sure about the procedure of completing the square your maths tutor should be familiar with it.
-2 plus 5 equals +3
x = 2 or x = 2/5