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Factors of 5 are only 1 and 5, which cannot lead to 2x, so using the quadratic formula (-2 +/- sqrt(4 - 20))/2 = (-2 +/- 4i))/2 = -1 +/- 2i which takes us into the realm of imaginary numbers...
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X2 plus 12x plus 36 equals 0?
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
X2 plus 2x - 15 equals 0?
x²+2x-15=0 x1=-2/2 - Square root of ((2/2)²+15) x1=-1-4 x1=-5 x2=-2/2 + Square root of ((2/2)²+15) x2=-1+4 x2=3
X2 plus 2x-4 equals 0?
x2+2x-4 = 0 x = (-2 plus/minus sqrt (4-(4x1x-4)) / 2 x = (-2 plus/minus sqrt 20)/2 x = (-2 - sqrt 20)/2 or (-2 + sqrt 20)/2 x = -3.236 or 1.236
Solve X3 plus X2-8X-6 equals 0?
x3 + x2 - 8x - 6 = 0 x3 + 3x2 - 2x2 - 6x - 2x - 6 = 0 x2(x + 3) - 2x(x + 3) - 2(x + 3) = 0 (x + 3)(x2 - 2x - 2) = 0 The second bracket cannot be factorised, so applying the quadratic formula to it gives the answers as So x = -3 or x = 1 +/-sqrt(3) that is, x = -3, x = -0.732051 or x = 2.732051
X2 plus 36 equals 20x?
x2 + 36 = 20x so x2 - 20x + 36 = 0 so x2 - 2x - 18x + 36 = 0 or x(x - 2) - 18(x - 2) = 0 that is (x - 2)(x - 18) = 0 so x - 2 = 0 or x - 18 = 0 ie x = 2 or x = 18
