y = x2 + 2x + 1
zeros are:
0 = x2 + 2x + 1
0 = (x + 1)(x + 1)
0 = (x + 1)2
x = -1
So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
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You must add 1
x2 - 2x - 5 = 0 x2 - 2x + 1 = 6 (x - 1)2 = 6 x - 1 = ± √6 x = 1 ± √6
x=1
A graph that has 1 parabolla that has a minimum and 1 positive line.
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5